2 years ago

Find S8 for the geometric series 3 + -6 + 12 + -24 +…

1 answer:

6 0

I guess you are asking to find the sum of the first 8 terms. If so, then:
Sum = a₁(1-rⁿ)/(1-r), where a₁ is the 1st term, r=common ratio and n=number of terms:
the 1st term a₁ =3
common ratio r = - 2 (since -6/3 = - 2, and 12/-6 = - 2, etc.)

Sum = 3[(1- (-2)⁸]/(1-2) = 3(1- 256)/(1/2)
Sum = -1530

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Answer:

k = 18

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Step-by-step explanation:

x = k * y * z

Find k when x = 4, y = 3, and z = 24

4 = k * 3 * 24

4 = k * 72

4 = 72k

k = 72/4

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find z when x = -3 and y = 4

x = k * y * z

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