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Ivanshal [37]
4 years ago
5

A big ship drops its anchor. E(t) models the anchor's elevation relative to the water's surface (in meters) as a function of tim

e t (in seconds). E(t)=−2.4t+75 How far does the anchor drop every 5 seconds?
Mathematics
2 answers:
Nezavi [6.7K]4 years ago
5 0

Answer:

<h2>The anchor drops 12 meters every 5 seconds, assuming that it moves constantly.</h2>

Step-by-step explanation:

The given function is

E(t)= -2.4t+75

Where E(t) models the anchor's elevations in relation to the water's surface. Notice that the function depends on the time.

Now, to find how far does the anchor drop every 5 seconds, we just need to replace t=5

E(5)= -2.4(5)+75=-12+75=63

However, we just need the rate per second, which doesn't include the initial condition of 75 meters, because that's would  mean we are gonna give the total meters.

2.4(5)=12

Therefore, the anchor drops 12 meters every 5 seconds, assuming that it moves constantly.

forsale [732]4 years ago
3 0
Plug in 5 for t, while ignoring the +75.
2.4(5) = 12
Therefore, the anchor drops 12 m. every 5 seconds
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