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kkurt [141]
3 years ago
6

How to put the following in order largest to smallest 0.20.7569%

Mathematics
1 answer:
MakcuM [25]3 years ago
8 0
0.2, 0.75, 60%, 1/2, 1, 1 1/4

60% is the same as 60/100 or 0.6
1 1/4 is the same as 5/4 or 1.25
1/2 is the same as 0.5
Now our list is 

0.2, 0.75, 0.6, 0.5, 1.25 and 1

So from largest to smallest your answer would be...

1.25 , 1 , 0.75 , 0.6 , 0.5 , 0.2
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A regular octagon has an apothem of 16.9 cm and a side length of 14 cm. Find the area to the nearest tenth.
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2 years ago
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The offices of​ president, vice​ president, secretary, and treasurer for an environmental club will be filled from a pool of 15c
Alexus [3.1K]

Answer:

a) 5.13% probability that all of the offices are filled by members of the debate​ team

b) 2.56% probability that none of the offices are filled by members of the debate​ team

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the people are chosen is important, since the first person is the president, the second is the vice president and so on... So we use the permutations formula to solve this question.

Permutations formula:

The number of possible permutations of x elements from a set of n elements is given by the following formula:

P_{(n,x)} = \frac{n!}{(n-x)!}

​(a) What is the probability that all of the offices are filled by members of the debate​ team?​

Desired outcomes:

4(president, vice​ president, secretary, and treasurer) offices from a set of 8(candidates of the members debate team).

So

D = P_{(8,4)} = \frac{8!}{(8-4)!} = 1680

Total outcomes:

4 offices from a set of 15 candidates.

T = P_{(15,4)} = \frac{15!}{(15-4)!} = 32760

Probability:

P = \frac{D}{T} = \frac{1680}{32760} = 0.0513

5.13% probability that all of the offices are filled by members of the debate​ team

(b) What is the probability that none of the offices are filled by members of the debate​ team?

Desired outcomes:

4(president, vice​ president, secretary, and treasurer) offices from a set of 7(candidates who are not of the members debate team).

D = P_{(7,4)} = \frac{7!}{(7-4)!} = 840

Total outcomes:

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T = P_{(15,4)} = \frac{15!}{(15-4)!} = 32760

Probability:

P = \frac{D}{T} = \frac{840}{32760} = 0.0256

2.56% probability that none of the offices are filled by members of the debate​ team

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