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ycow [4]
3 years ago
9

A mutation is _____.

Computers and Technology
1 answer:
Kipish [7]3 years ago
8 0

Answer:

I am explain you in image

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Design and write an object-oriented program for managing inventory bins in a warehouse. To do this you will use two classes: Inv
andrew11 [14]

Answer:

#include <cstdlib>

#include <iostream>

using namespace std;

int main(int argc, char *argv[])

{

class InvBin {

private:

string description;

int qty;

 

public:

InvBin(){ description = ""; qty = 0;}

InvBin (string d, int q) { description = d; qty = q;}

void setDescription (string d){description = d;}

void setQty(int q){qty = q;}

string getDescription() {return description;}

int getQty(){ return qty; }

};

class BinManager {

private:

InvBin bin[30];

int numBins;

 

public:

BinManager() {numBins=0;}

BinManager(int size, string d[], int q[])

{

int i;

for(i=0; i<size; ++i)

{

bin[i].setDescription(d[i]);

bin[i].setQty(q[i]);

}

numBins = size;

}

void setDescription (int b, string d) {bin[b].setDescription(d); }

void setQty(int b, int q) { bin[b].setQty(q); }

string getDescription(int b) { return bin[b].getDescription();}

int getQty(int b) { return bin[b].getQty();}

bool addParts(int b, int q)

{

int temp;

if(q < 1)

return false;

else

{

temp = bin[b].getQty() + q;

bin[b].setQty(temp);

return true;

}

}

bool removeParts(int b, int q)

{

int temp;

if (q < 1 || bin[b].getQty() < q)

return false;

else

{

temp = bin[b].getQty() - q;

bin[b].setQty(temp);

return true;

}

string displayAllBins()

{

int i;

for(i=0;i<numBins;++i)

cout << i+1 << ". " << left<< setw(20) << bin[i].getDescription()

<< right << setw(4) << bin[i].getQty() << endl;

}

};

system("PAUSE");

return EXIT_SUCCESS;

}

Explanation:

3 0
2 years ago
What did I do wrong? May you please correct it for me...I was also looking on how to delay when it prints. Like when it prints a
inessss [21]

Answer:

print("\nWelcome to the impossible quiz!\n")

name = input("What's your name before we get started? ")

print("Nice to meet you, "+ name)

print("\nThe rules are very simple, get the answer right and you get 10 points. You only have one chance to get the answer right, get it wrong and you'll lose 3 points! ")

input("\nReady?\n")

user_score = 0

print("First question: Do slugs have four noses?")

answer = input('Give "F" for False or "T" for True: ')

if answer == "T":

time.sleep(2)

print("Correct, you've gained 10 points!")

user_score += 10

elif answer == "F":

time.sleep(2)

print("Incorrect, you've lost 3 points!")

user_score += -3

Explanation:

Please check the answer. However, if before answer was wrong, and we need to use time.sleep(2) for delaying printing.

4 0
3 years ago
Which is a good way to improve your credit score
labwork [276]
Pay your bills and don't be late
8 0
3 years ago
Technologies are having a negative impact on businesses.
Aloiza [94]

Answer: False

Explanation: I think its false because technologie has had a good impact on businesses.

4 0
3 years ago
Write a piece of codes that asks the user to enter a month (an integer), a day (another integer), and a two-digit year. The prog
Sliva [168]

Answer:

Follows are the code to this question:

#include <iostream>//header file

using namespace std;

int main()//main method

{

int day,month,year;//defining integer variable

cout<<"please enter last two digit of the year: "; //print message

cin>>year;//input year value

cout<<"enter day: "; //print message

cin>>day;//input day value

cout<<"enter month: ";//print message

cin>>month;//print month message

if(month*day==year)//check magic date condition  

{

cout<<"its magic programology year";//print message

}

else

{

cout<<"its not magic year";//print message

}

return 0;

}

Output:

please enter last two digit of the year: 98

enter day: 14

enter month: 7

its magic programology year

Explanation:

In the given code, three integer variable "day, month, and year" is declared, that uses the input method "cin" to input the value from the user-end.

In the next step, an if block statement is used that check month and day value multiple is equal to year value, if the condition is true it will print "magic programology year" otherwise it will print "not the magic year".

6 0
3 years ago
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