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ycow [4]
3 years ago
9

A mutation is _____.

Computers and Technology
1 answer:
Kipish [7]3 years ago
8 0

Answer:

I am explain you in image

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What correlation is obtained when the pearson correlation is computed for data that have been converted to ranks?
professor190 [17]

The correlation that is obtained when the pearson correlation is computed for data that have been converted to ranks is option A) The Spearman correlation.

<h3>What is Spearman correlation used for?</h3>

Spearman's correlation is known to be one that tends to look into or measures the strength and way of monotonic relationship between two variables.

It is one that is a nonparametric measure that is often known to be rank correlation and it tends to examine  how well the association between two variables can be said to using a monotonic function.

Hence, The correlation that is obtained when the pearson correlation is computed for data that have been converted to ranks is option A) The Spearman correlation.

Learn more about correlation from

brainly.com/question/12479370

#SPJ4

See full question below

) What correlation is obtained when the Pearson correlation is computed for data that have been converted to ranks?

A) The Spearman correlation

B) The point-biserial correlation

C) The phi coefficient

D) It is still called a Pearson correlation

8 0
2 years ago
Gauthmath https://s.tutorus.xyz/lp/invite?code=GGQGBL​
sammy [17]

Answer:

Umm

Explanation:

3 0
2 years ago
Array Challenge Have the function ArrayChallenge (arr) take the array of numbers stored in arr and return the string true if any
vampirchik [111]

Answer:

The code is given as follows,

Explanation:

Code:

#include <stdio.h>

#include <string.h>  

int n; //to store size of array  

char* ArrayChallenge(int arr[]) //function returns string true or false

{

  int i, j;

  int sum = 0;

  for(i = 0; i < n; i++)

  {

      sum = sum + arr[i]; //count sum

  }  

  for(i = 0; i < n; i++)

  {

      for(j = i+1; j < n; j++) //loop for every two elements in array

      {

          if(arr[i]*arr[j] > 2*sum) //check if proudct of two elements > 2 times sum

          {

              printf("\n%d x %d = %d, 2xSum = %d\n", arr[i], arr[j], arr[i]*arr[j], 2*sum);

              return "true"; //If proudct of two elements > 2 times sum. return true

          }

      }

  }

  return "false"; // If proudct of two elements < 2 times sum. return false

}  

int main()

{  

  printf("\nEnter size of array: ");

  scanf("%d", &n); //read size of array

  int A[n]; //array of size n

  printf("\nEnter array elements: ");

  int i;

  for(i = 0; i < n; i++)

  {

      scanf("%d", &A[i]); //read array from stdin

  }

  printf("%s\n",ArrayChallenge(A)); //ccall function and print answer

 

  return 0;

}

6 0
3 years ago
Anybody want to help me figure out how to put this on a resumè
Svet_ta [14]

Answer:

OMG IM LIKE BLUSHING AS DARK AS A TOMATO RIGHT NOW

5 0
3 years ago
A prime number is a number that is divisible only by itself and 1. Write a program that asks a user for an integer value and the
Rashid [163]

Answer:

The Solution Code is written in Java.

  1. public class Main {
  2.    public static void main(String[] args) {
  3.        System.out.print("Please enter an integer: ");
  4.        Scanner input = new Scanner(System.in);
  5.        int number = input.nextInt();
  6.        System.out.print("Prime numbers less than or equal to " + number + " : ");
  7.        for(int i=2; i <= number; i++){
  8.            if(checkPrime(i)){
  9.                System.out.print(i + " ");
  10.            }
  11.        }
  12.    }
  13.    public static Boolean checkPrime(int num){
  14.        for(int i=2; i < num; i++)
  15.        {
  16.            if(num % i == 0){
  17.                return false;
  18.            }
  19.        }
  20.        return true;
  21.    }
  22. }

Explanation:

Firstly, we create a function to check if a number is prime (Line 18 - 27).

  • This function will take one input value which is an integer, num.
  • To check if the input num is a prime, we can use modulus operator, %, to confirm if the num is divisible by any number starting from 2 to num - 1 (Line 19 - 24).
  • If the num is divisible by any number expect 1 and itself, it should equal to zero and return false to indicate it is not a prime number.
  • If all the num (except 1 and itself) is not divisible, the function will return true (Line 25).

Next, in our main program part (Line 3 - 16)

  • Prompt the user to input a number (Line 5 - 7)
  • Using a for-loop, we can keep calling the checkPrime() function by passing a current number (starting from 2 to input number) as argument (Line 12). The checkPrime() function will run and return true it the current number is prime, return false if it is not prime.
  • If the checkPrime() function return true, it will print the current number before proceed to the iteration of the for-loop to repeat the same check prime procedure (Line 13)
  • At the end all the prime numbers less than or equal to the input number will be printed out in the terminal
8 0
3 years ago
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