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3 years ago

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Question 20 Unsaved The graph below represents changes in water. What process is occurring during section "B" of the graph? Ques

tion 20 options: vaporization condensation freezing melting

2 answers:

juin [17]3 years ago

5 0

melting ... happpens at constant temp

FinnZ [79.3K]3 years ago

4 0

melting ... happpens at constant temp

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Luis wanted to know which of his 4 toy cars is the fastest. He conducted an experime and recorded his results in the table shown

Murrr4er [49]

The dependent variable was the time and the independent variable was thecars

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4 years ago

A tennis ball is shot vertically upward inside a tower with an initial speed of

LenaWriter [7]

The ball's height at time <em>t</em> is

<em>y</em> = (20.0 m/s) <em>t</em> - 1/2 <em>g</em> <em>t</em>²

where <em>g</em> is the acceleration due to gravity, with magnitude 9.80 m/s².

Also, recall that

<em>v</em>² - <em>u</em>² = 2 <em>a</em> ∆<em>y</em>

where <em>u</em> is the initial velocity, <em>v</em> is the final velocity, <em>a</em> is the acceleration, and ∆<em>y</em> is the change in height. Let <em>Y</em> be the maximum height. At this height, <em>v</em> = 0, so

- (20.0 m/s)² = 2 (-<em>g</em>) <em>Y</em>

==> <em>Y</em> ≈ 20.408 m

Plug this into the first equation and solve for <em>t</em> :

<em>Y</em> = (20.0 m/s) <em>t</em> - 1/2 (9.80 m/s²) <em>t</em>²

==> <em>t</em> ≈ 2.04 s

The ball's velocity at time <em>t</em> is

<em>v</em> = 20.0 m/s - <em>g</em> <em>t</em>

After <em>t</em> = 3.0 s, its velocity will be

<em>v</em> = 20.0 m/s - (9.80 m/s²) (3.0 s)

<em>v</em> = -9.40 m/s

or 9.40 m/s in the downward direction.

4 0

3 years ago

A rocket fired two engines simultaneously. One produces a thrust 725 N directly forward while the other gives a 513N thrust at 3

dezoksy [38]

Answer:

Magnitude of resultant force is 1190.314 N

Direction of force is 13.352°

Explanation:

given data:

thrust force = 725 N

Angle = 32.4 degree

Let x is consider as positive direction

Resultant force in x direction is

Rx = 725 + 513cos32.4 = 1158.14 N

and Resultant force perpendicular to x direction is:

Ry = 513sin32.4 = 274.88 N

Magnitude of resultant force is

$R=\sqrt{R_x^2+R_y^2} = 1190.314N$

and resultant force direction is

$\theta=tan^{-1}\frac{R_y}{R_x} = 13.352\degree$

7 0

4 years ago

A uniform, thin, solid door has height 2.20 m, width 0.870 m, and mass 23.0 kg. (a) find its moment of inertia for rotation on i

vampirchik [111]

The solution for this problem is:

a. The moment of inertia of the thin door rotating about the hinges axis is given by:

I = 1/3 mw^2 is to solve for the inertia, where: m is the mass and w is the width

= 23.0 x 0.870^2 / 3

= 17.4087 / 3

= 5.8029 kg m^2

b. The height of the door is not required for this calculation.

8 0

3 years ago

A drowsy cat is looking at a window from across the room, and sees a flowerpot that sail first up and then down past the window.

vodka [1.7K]

Answer:

1.54 m

Explanation:

The time the cat sees the pot going up will be half of the total time the cat saw the pot. The same is true for the pot going down.

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.81 m/s²

$s=ut+\frac{1}{2}at^2\\\Rightarrow u=\frac{s-\frac{1}{2}at^2}{t}\\\Rightarrow u=\frac{1.84-\frac{1}{2}\times -9.81\times 0.27^2}{0.27}\\\Rightarrow u=8.14\ m/s$

$v=u+at\\\Rightarrow v=8.14-9.81\times 0.27\\\Rightarrow v=5.5\ m/s$

This will be the initial velocity while going up higher

$v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-5.5^2}{2\times -9.81}\\\Rightarrow s=1.54\ m$

The the flower pot will go 1.54 m above the window

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3 years ago