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Lorico [155]
3 years ago
8

You drive 3.4 km in a straight line in a direction 6.9º east of north. If an alternate route to this same destination takes you

straight east and then turns directly north to arrive at the same point, find the distance you would have to drive north.
Physics
1 answer:
Scrat [10]3 years ago
3 0

Answer:

You would have to drive in north direction 0.41km

Explanation:

We can solve this with trigonometry, We know that:

sin(\alpha )=\frac{opposite}{hypotenuse}\\where: \\opposite=north\\hypotenuse=distance

North=sin(6.9^o)*3.4km=0.41km

So the distance I will have to drive in north direction is 0.41km

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The frequency of a physical pendulum comprising a nonuniform rod of mass 1.15 kg pivoted at one end is observed to be 0.658 Hz.
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The rotational inertia of the pendulum around its pivot point is 0.280\,kg\cdot m^{2}.

Explanation:

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Where:

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m - Mass of the physical pendulum, measured in kilograms.

g - Gravitational constant, measured in meters per square second.

d - Straight line distance between the center of mass and the pivot point of the pendulum, measured in meters.

I_{O} - Moment of inertia with respect to pivot point, measured in kg\cdot m^{2}.

In addition, frequency and angular frequency are both related by the following formula:

\omega =2\pi\cdot f

Where:

f - Frequency, measured in hertz.

If f = 0.658\,hz, then angular frequency of the physical pendulum is:

\omega = 2\pi \cdot (0.658\,hz)

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From the formula for the physical pendulum's angular frequency, the moment of inertia is therefore cleared:

\omega^{2} = \frac{m\cdot g \cdot d}{I_{o}}

I_{o} = \frac{m\cdot g \cdot d}{\omega^{2}}

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I_{o} = \frac{(1.15\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (0.425\,m)}{\left(4.134\,\frac{rad}{s} \right)^{2}}

I_{o} = 0.280\,kg\cdot m^{2}

The rotational inertia of the pendulum around its pivot point is 0.280\,kg\cdot m^{2}.

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