What did scientists discover when they arranged elements in order of increasing atomic mass?

1 answer:

4 0

<span>The scientists discovered that when they organized elements in order of increasing atomic mass there is a pattern of repetition of properties (A). The periodic law was developed by Dmitri Mendeleev and Lothar Mayer in 1869. They worked independently of each other and both created a periodic table. They both arranged the items on the table by weight and both suggested that certain properties of the elements recur. The Mendeleev table is the most important table because the values for the atomic mass are the most accurate.</span>

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Please Help I need an explanation on how to do this

nydimaria [60]

Balanced equation(That should be NaClO_3)

$\\ \rm\Rrightarrow Cl_2+2NaOH\longrightarrow NaCl+NaClO_3+H_2O$

Remember that it's a ionic equation not general equation

We have to balance it accordingly

5 0

2 years ago

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A beaker of nitric acid is neutralized with dilute aqueous solution of calcium hydroxide.Write a net ionic equation for this rea

Soloha48 [4]

Complete balanced equation: 2HNO₃ + Ca(OH)₂ → Ca(NO₃)₂ + 2H₂O

Ionized equation (with spectator ions):
2H⁺ + 2NO₃⁻ + Ca²⁺ + 2OH⁻   → Ca²⁺ + 2NO₃⁻ + 2H₂O

By eliminating the ions that are the same of both sides of the equation (spectator ions):

2H⁺ + 2OH⁻   → 2H₂O [Net Ionic Equation]

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3 years ago

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Reika [66]

Because potassium is a gas that can evolve

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3 years ago

Compound a is an alkene that was treated with ozone (followed by dms) to yield only 4-heptanone. Draw the major product that is

olga nikolaevna [1]

Alkenes on reacting with ozone results in the formation of ozonide which undergo reductive cleavage in presence of dimethyl sulfide to form carbonyl compounds (aldehyde or ketone). Whereas in presence of hydrogen peroxide it undergoes oxidative cleavage to form carboxylic acids or ketones.

Since, A alkene yields 4-heptanone only on treatment with ozone and DMS thus, it implies that both the chains on the side of the double-bond are similar the product is 4-heptanone that means the double bond is present between the chains at the 4th carbon. Therefore the structure of compound A is 4,5-dipropyloct-4-ene.

The reaction is as shown in the image.

The reaction of A with m-CPBA (meta-perchlorobenzoic acid) followed by aqueous acid $H_3O^{+}$ is shown in the image.

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Answer D moles per L

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