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Nuetrik [128]
3 years ago
12

In preparation for a demonstration, your professor brings a 1.50−L bottle of sulfur dioxide into the lecture hall before class t

o allow the gas to reach room temperature. If the pressure gauge reads 173 psi and the lecture hall is 20°C, how many moles of sulfur dioxide are in the bottle? In order to solve this problem, you will first need to calculate the pressure of the gas. Hint: The gauge reads zero when 14.7 psi of gas remains.
Chemistry
1 answer:
Marrrta [24]3 years ago
6 0

Answer:

0.66 mol

Explanation:

Zero Gauge pressure = 14.7 psi

Pressure read = 173 psi

Actual pressure = 173 psi - 14.7 psi = 158.3 psi

P (psi) = 1/14.696  P(atm)

So, Pressure = 10.77 atm

Given that:

Temperature = 20 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T₁ = (20+ 273.15) K = 298.15 K

V = 1.50 L

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L atm/ K mol  

Applying the equation as:

10.77 atm × 1.50 L = n ×0.0821 L atm/ K mol  × 298.15 K

⇒n = 0.66 mol

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kolezko [41]

Answer: 1.274 * 10^ -7 meter (same as 127.4 nanometers

Explanation:

It's given that the energy

required to break the N N triple bond is 945 * 10^3 joules per mole.

One mole contains 6.02 * 10^ 23 molecules, so the energy required per molecule

= 945 * 10^3 / 6.023 * 10^23, or 1.56 * 10^-18 joules.

Then we need a photon whose energy (E) is at least that amount.

The energy E of a photon is related to its frequency f by PLANCK'S EQUATUON,

E = hf,

where h is Planck's constant (6.625 * 10^-34 joule-sec)

and the wavelength w is inversely proportional to the frequency by w = c/f, where c is the speed of light, 2.998 * 10^8 meters per sec.

If h & c are both constants, their product hc is constant, so we can say E = hc/w,

or if we know E and want to find w, a little algebra gives: w = hc/E.

The product hc = 1.9875 * 10^-25 joule-meters,

so w = 1.9875 * 10^-25 / 1.56 * 10^-18, or 1.274 * 10^ -7 meter (same as 127.4 nanometers

6 0
3 years ago
How many hydrogen atoms are in CH2OH?<br><br> a-10<br> b-3<br> c-5<br> d-4
igomit [66]

Answer:

B)3

Explanation:

I'm assuming the 2 is meant to be smaller. If it were a regular size 2 the answer would be 2 and that isn't an option

7 0
3 years ago
Read 2 more answers
What is the difference between pH and pOH?
natali 33 [55]

Answer:

pH measures ratio of H+ ions to OH- ions of substances

pOH measures ratio of OH- ions to H+ ions of substances

Explanation:

pH is a scale which measures the ratio of H+ ions to OH- ions to identify how acidic or basic a substance is. This is because acidic substances have high amounts of H+ ions and low amounts of OH- ions, and therefore have a higher ratio of H+ to OH- ions. (And vice versa for bases, low H+ to OH- ratio) On a pH scale, acidic substances have a pH of 0 to 7, water (neutral pH, not acidic nor basic) has a pH of 7, and bases have a pH of 7-14.

pOH is very similar to pH but measures the opposite: the ratio of OH- ions (indicative of a base) to H+ ions (indicative of an acid). Therefore the pH values are reversed on the scale: Basic substances have pOHs below 7, and acidic substances are above 7 on the pOH scale.

Fundamentally, these two scales measure the same thing is the same way, one just measures the ratio one way (H+:OH-), while the other measured them the other way (OH-:H+), resulting in flipped values on the scales:

pH: 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14

      <---Acidic--->   <------Basic------->

pOH: 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14

         <----Basic---->  <-----Acidic------->

Hope this helped!

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Plz answer ASAP
strojnjashka [21]

Answer:

this should help *not a virus

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https://kidshealth.org/en/teens/digestive-system.html

6 0
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what temperature change will be observed if a sample of 100 g of ethylene glycol antifreeze solution (specific heat capacity = 3
ivolga24 [154]

Answer:

1°C temperature change will be observed if a sample of 100 g of ethylene glycol antifreeze solution.

Explanation:

Mass of ethylene glycol = m = 100 g

Specific heat capacity of ethylene glycol = c = 3.5 J/g°C

Change in temperature of ethylene glycol = ΔT

Heat loss by the ethylene glycol = Q = 350 J

Q=mc\Delta T

\Delta T=\frac{Q}{mc}=\frac{350 J}{100 g\times 3.5 J/g^oC}

ΔT = 1°C

1°C temperature change will be observed if a sample of 100 g of ethylene glycol antifreeze solution.

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