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Gre4nikov [31]
3 years ago
8

A 25.0 mL solution of a monoprotic weak acid is titrated with 0.10 M NaOH. The equivalence point is reached after 38.52 mL of Na

OH has been added. What was the initial concentration of the weak acid
Chemistry
1 answer:
Sveta_85 [38]3 years ago
8 0

Answer:

0.154 M

Explanation:

In case of titration , the following formula can be used -

M₁V₁ = M₂V₂

where ,

M₁ = concentration of acid ,

V₁ = volume of acid ,

M₂ = concentration of base,

V₂ = volume of base .

from , the question ,

M₁ = ? M

V₁ = 25.0mL

M₂ = 0.10 M

V₂ = 38.52 mL

Using the above formula , the molarity of acid , can be calculated as ,

M₁V₁ = M₂V₂  

Putting the respective values ,

M₁ * 25.0mL =  0.10 M * 38.52 mL

M₁ = 0.154 M

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How many electron are in 56fe 3
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Each proton has a charge of +1. The other particle present in the nucleus - the neutron - has zero electrical charge and thus irrelevant when computing the charge of a nucleus. It is easy to deduce that the nucleus charge equals the number of protons (which in turn equals the atomic number). So the nucleus charges are:
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7 0
3 years ago
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Galina-37 [17]

Explanation:

Refer to attachment.

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6 0
3 years ago
A sample of black coffee was measured to have [h3o+] = 7.94 × 10−6. what is true about this solution?
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Because the pH is less than 7 (within the range 1 to 6), then the black coffee solution is acidic. </span>
6 0
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