Answer:
oxygen molecule has two oxygen atom . Each O atom share 2 electrons to form two covalent bonds out of which one is sigma bond and other is pi bond . sigma bond is formed by axial overlap 2p atomic orbitals of oxygen and pi bond is formed of lateral overlap of 2p atomic orbitals of oxygen .
A wave with a smaller wavelength has more energy than one with a larger wavelength.
Answer:
c) Check to see if there's a better medication for the patient's problem.
d) Dispense an extra dose to save the patient from having to return in case of loss or damage to one of the doses.
e ) Compare the label on the medication with the order from the physician .
<u>Answer:</u> The wavelength of spectral line is 656 nm
<u>Explanation:</u>
To calculate the wavelength of light, we use Rydberg's Equation:
![\frac{1}{\lambda}=R_H\left(\frac{1}{n_f^2}-\frac{1}{n_i^2} \right )](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5Clambda%7D%3DR_H%5Cleft%28%5Cfrac%7B1%7D%7Bn_f%5E2%7D-%5Cfrac%7B1%7D%7Bn_i%5E2%7D%20%5Cright%20%29)
Where,
= Wavelength of radiation
= Rydberg's Constant = ![1.097\times 10^7m^{-1}](https://tex.z-dn.net/?f=1.097%5Ctimes%2010%5E7m%5E%7B-1%7D)
= Final energy level = 2
= Initial energy level = 3
Putting the values in above equation, we get:
![\frac{1}{\lambda }=1.097\times 10^7m^{-1}\left(\frac{1}{2^2}-\frac{1}{3^2} \right )\\\\\lambda =\frac{1}{1.524\times 10^6m^{-1}}=6.56\times 10^{-7}m](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5Clambda%20%7D%3D1.097%5Ctimes%2010%5E7m%5E%7B-1%7D%5Cleft%28%5Cfrac%7B1%7D%7B2%5E2%7D-%5Cfrac%7B1%7D%7B3%5E2%7D%20%5Cright%20%29%5C%5C%5C%5C%5Clambda%20%3D%5Cfrac%7B1%7D%7B1.524%5Ctimes%2010%5E6m%5E%7B-1%7D%7D%3D6.56%5Ctimes%2010%5E%7B-7%7Dm)
Converting this into nanometers, we use the conversion factor:
![1m=10^9nm](https://tex.z-dn.net/?f=1m%3D10%5E9nm)
So, ![6.56\times 10^{-7}m\times (\frac{10^9nm}{1m})=656nm](https://tex.z-dn.net/?f=6.56%5Ctimes%2010%5E%7B-7%7Dm%5Ctimes%20%28%5Cfrac%7B10%5E9nm%7D%7B1m%7D%29%3D656nm)
Hence, the wavelength of spectral line is 656 nm
Answer:
Characteristics. They are all relatively inert, corrosion-resistant metals. Copper and gold are colored. These elements have low electrical resistivity so they are used for wiring.
Explanation:
Hope this help u
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