Answer:
0.56 g
Explanation:
<em>A chemist determines by measurements that 0.020 moles of nitrogen gas participate in a chemical reaction. Calculate the mass of nitrogen gas that participates.</em>
Step 1: Given data
Moles of nitrogen gas (n): 0.020 mol
Step 2: Calculate the molar mass (M) of nitrogen gas
Molecular nitrogen is a gas formed by diatomic molecules, whose chemical formula is N₂. Its molar mass is:
M(N₂) = 2 × M(N) = 2 × 14.01 g/mol = 28.02 g/mol
Step 3: Calculate the mass (m) corresponding to 0 0.020 moles of nitrogen gas
We will use the following expression.
m = n × M
m = 0.020 mol × 28.02 g/mol
m = 0.56 g
Answer:
moves molecules
Explanation:
I did this one yesterday! Active transport moves low to high concentration and passive does the opposite so C and D are not an option. Active transport requires energy and Passive Transport does not so it has to be A.!
Answer:
The partial pressure of CO is 5.54x10⁻⁴⁹atm. You shouldn't worry because it is very low pressure
Explanation:
First, the balanced reaction is:
CO + 1/2O₂ → CO₂
The energies of formation are:
ΔG(CO)=-137.168kJ/mol
ΔG(O₂)=0
ΔG(CO₂)=-394.359kJ/mol
The energy of the reaction is:

The expression for calculate the partial pressure of CO is:

the answer is thermal.......
Do you mean h=7.0+10? If so your answer is 70.