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Crank
3 years ago
5

Angular diameter of the Sun from the Earth orbit is approximately 32′ (arc minutes), and the solar constant is 1.36kWt/m2 . (a)

What is the Sun’s radius? (b) How much total power does the Sun emit? (c) What is the power flux on the surface of the Sun?
Physics
1 answer:
Burka [1]3 years ago
4 0

Answer:

a) 1392.54 *10^6 m

b) 3.8248284*10^26 W

c) 6.2783674*10^7 W/m^2

Explanation:

from the exercise we have the following values:

angular diameter of sun from earth, phi = 32'

solar constant, S = 1.36 kW/m^2

a. distance of sun from earth, d = 149.6*10^9 m

therefore

phi = D/d

clear D

D = d*phi

so we have

a) diameter of sun = D

D = 1392.54 *10^6 m

b. How much total power does the Sun emit? =P

P = S*4*pi*d^2

P= = 3.8248284*10^26 W

c. power flux on surface of sun = P/pi*D^2

c. power flux on surface of sun  = 6.2783674*10^7 W/m^2

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C = (200-32) * (5/9) = 93.333334 degrees Celsius

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A 35.9 g mass is attached to a horizontal spring with a spring constant of 18.4 N/m and released from rest with an amplitude of
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Answer:

7.74m/s

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V = √(59.966)

V = 7.74m/s

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