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Crank
3 years ago
5

Angular diameter of the Sun from the Earth orbit is approximately 32′ (arc minutes), and the solar constant is 1.36kWt/m2 . (a)

What is the Sun’s radius? (b) How much total power does the Sun emit? (c) What is the power flux on the surface of the Sun?
Physics
1 answer:
Burka [1]3 years ago
4 0

Answer:

a) 1392.54 *10^6 m

b) 3.8248284*10^26 W

c) 6.2783674*10^7 W/m^2

Explanation:

from the exercise we have the following values:

angular diameter of sun from earth, phi = 32'

solar constant, S = 1.36 kW/m^2

a. distance of sun from earth, d = 149.6*10^9 m

therefore

phi = D/d

clear D

D = d*phi

so we have

a) diameter of sun = D

D = 1392.54 *10^6 m

b. How much total power does the Sun emit? =P

P = S*4*pi*d^2

P= = 3.8248284*10^26 W

c. power flux on surface of sun = P/pi*D^2

c. power flux on surface of sun  = 6.2783674*10^7 W/m^2

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w = 17.1 / 0.47

w = 36.38 rad/s

Now, substituting the value of w, with the already given value of I in the equation, we have

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KE(rot) = 1/2 * 0.5 * 36.38²

KE(rot) = 0.25 * 1323.5

KE(rot) = 330.88 J

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3 years ago
In science, a hypothesis must be true.
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I would believe that this is false.
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7 0
2 years ago
Read 2 more answers
Two particles P and Q each moves towards ther along Straight Line (M)(N), 51m long. P starts from M with velocity 5m/s and const
bagirrra123 [75]

The time required by the particles are as follows:

a. t = 1.5 seconds

b. t = 3 seconds

c. t = 0.4 seconds

<h3>What is the time required?</h3>

The time required for the particles to be at several distances apart is calculated using the equation of motion given below:

S = ut + \frac{1}{2}at^{2}

a) Time required to be 30 m apart:

Assuming the distance covered by P is S1 and distance covered by Q is S2.

S1 + S2 = 51 - 30

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Substituting the values of velocity and acceleration in the equation of motion above:

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2t^2 + 11t - 21 = 0

Solving for time, t by factorization, t = 1.5 seconds

b) Time required to meet:

Assuming the distance covered by P is S1 and distance covered by Q is S2.

S1 + S2 = 51

Substituting the values of velocity and acceleration in the equation of motion above:

5t + 1/2t^2 + 6t + 3t^2 = 51

2t^2 + 11t - 51 = 0

Solving for time, t by factorization, t = 3 seconds

c) Time required for velocity of P is ¾ of the velocity of Q:

Using the equation of motion: V = u + at

Vp = 3/4 Vq

4Vp= 3Vq

Substituting the values:

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5t = 2

t = 0.4 seconds

Learn more about distance, velocity and acceleration at: brainly.com/question/14344386

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7 0
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