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PIT_PIT [208]
3 years ago
14

Two charged particles, with charges q1 = q and q2 = 4q are located at a distance d = 2cm apart on the x axis A third charged par

ticle, with charge q3 = q is placed on the x axis such that the magnitude of the force that charge 1 exerts on charge 3 is equal to the force that charge 2 exerts on charge 3. Find the position of charge 3 when q = 10n C
Physics
1 answer:
weqwewe [10]3 years ago
3 0

Answer:

0.667 cm

Explanation:

|F_1on3| = |F_2on3|

k×q1×q3/x^2 = k×q2×q3/(d-x)^2

q1/x^2 = q2/(d-x)^2

(d-x)^2/x^2 = q2/q1

(d-x)/x = sqrt(q2/q1)

(2 - x)/x = sqrt(4×q/q)

(2 - x)/x = 2

2 - x = 2x

2 = 3x

x = 2/3

x= 0.667 cm

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In which scenario does radiation occur? warming soup on a stove drying towels at the beach cooking eggs in boiling water warming
shepuryov [24]

Answer: drying towels at the beach.

Explanation:

Radiation simply has to do with the energy that is gotten from a particular source and then goes through some materials. It simply means the way energy is being transmitted as waves or heat through a certain medium.

From the options given, the scenario whereby a radiation takes place is when drying towels on the beach.

8 0
3 years ago
Read 2 more answers
Determine the components of reaction at the fixed support
denis-greek [22]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The components of reaction at the fixed support are  

    A_{(x)}  = 400  \ N ,  A_{(y)}  = -500  \ N ,  A_{(z)}  = 600  \ N ,  M_x  = 1225 \  N\cdot m , M_y  = 750 \  N\cdot m ,  M_z  = 0 \  N\cdot m

Explanation:

Looking at  the diagram uploaded we see that there are two  forces acting along the x-axis on the fixed support    

   These force are  400 N  and  A_{(x)} [ i.e the reactive force of  400 N  ]

Hence the sum of forces along the x axis is mathematically represented as

        A_{(x)}  - 400  = 0

=>     A_{(x)}  = 400  \ N

Looking at  the diagram uploaded we see that there are two  forces acting along the y-axis on the fixed support  

   These force are  500 N  and  A_{(y)} [ i.e the force acting along the same direction with 500 N   ]

Hence the sum of forces along the x axis is mathematically represented as

        A_{(y)}  + 500  = 0

=>     A_{(y)}  = -500  \ N

Looking at  the diagram uploaded we see that there are two  forces acting along the z-axis on the fixed support  

       These force are  600 N  and  A_{(z)} [ i.e the reactive force of  600 N  ]

Hence the sum of forces along the x axis is mathematically represented as

        A_{(z)}  - 600  = 0

=>     A_{(z)}  = 600  \ N

Generally taking moment about A along the x-axis we have that

    \sum M_x  = M_x  - 500 (0.75 + 0.5) + 600 ( 1 ) = 0

=>   M_x  = 1225 \  N\cdot m

Generally taking moment about A along the y-axis we have that

    \sum M_y  = M_y  - 400 (0.75 ) + 600 ( 0.75 ) = 0

=>   M_y  = 750 \  N\cdot m

Generally taking moment about A along the z-axis we have that

    \sum M_z  = M_z = 0

=>   M_z  = 0 \  N\cdot m

8 0
3 years ago
What is the charge of an atom that has lost one electron?
Luden [163]

Answer:

positive

An atom has a even amount of protons, electrons, and a little less neutrons. If the atom lost one electron, then it now has a positive charge.

Hope it helps!

5 0
3 years ago
Calculate the acceleration of a bus that speed up from 20ms-1 to 40ms-1 in 8 seconds?​
Anastaziya [24]

Answer:

2.5 ms^-2

Explanation:

acceleration

= (final velocity - initial velocity)/time

= [(40m/s) - (20m/s)]/8s

= (20m/s)/8s

= 5/2 m/s²

= 2.5 m/s²

= 2.5 ms^-2

3 0
3 years ago
average speed = distance covered divided by travel time. do some algebra and multiply both sides of this relation by travel time
mars1129 [50]
Based on the scenario,
The thing that the result say about distance covered is :
it tells you that the distance covered is equal to the average speed times the travel time

hope this helps
6 0
3 years ago
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