Answer:
the answer is 2.
Explanation:
Normal length of spring = 28.3 cm
stretched length of spring = 38.2 cm
length of extension = 38.2 - 28.3 = 9.9 cm
= 9.9 x 10⁻² m
force applied to stretch = .55 x 9.8 ( mg )
= 5.39 N
Force constant = force applied / extension
= 5.39 / 9.9 x 10⁻²
= .5444 x 10² N /m
= 54.44 N/m
Normal force=7.48 N
N+F~1 sinθ-mg=0
=>N=1.5*9.8-12 sin37◦
=>N=14.7-7.22=7.48 N
This is your answer
2.78 X 10^5 is the best answer to be responded to
