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3 years ago

What is the approximate increase in size from a 1 w to a 2w carbon resistor?

1 answer:

8 0

Since the 2-watt jobber has to dissipate twice as much power as the smaller unit I would expect it to have double the surface area. So if they are the usual cylindrical striped resistors then the larger one could have either double the length or else 1.4 times the radius of the smaller one.

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Warm air:

Andrei [34K]

Answer:

Explanation:

because warm air is less dense, and warm air rises and cold air sinks. (did research) hope this helps!! :)

4 0

4 years ago

Read 2 more answers

A heat engine does 9200 J of work per cycle while absorbing 22.0 kcal of heat from a hightemperature reservoir. What is the effi

Morgarella [4.7K]

Answer: 9.9%

Explanation: efficiency = (work output /work input) × 100

Note that, 1 kilocalorie = 4184 joules, hence 22kcal = 22× 4184 = 92048 joules.

Work output = 9200 j and work input = 92048 j

Efficiency = (9200/92048) × 100 = 0.099 × 100 = 9.9%

4 0

3 years ago

You are in a hot air balloon, 350 m above the flat Texas plains. You look out toward the horizon. How far out can you see--that

pshichka [43]

Refer to the diagram shown below.

x = the distance (horizon) that you can see from the balloon,

Because the radius of the earth is 6400 km, and the balloon is 350 n above the earth's surface, therefore
h = 6400 + 0.350 = 6400.35 km.

From the Pythagorean theorem, obtain
x = √(6400.35² - 6400²) = 66.934 km

Answer: Your horizon is 66.934 km (or 66,934 m)

3 0

3 years ago

Two charged particles are placed 2.0 meters apart. The first charge is +2.0 E-6 C, and the second charge is +4.0 E-6 C. What is

Anestetic [448]

The electrical force between the two charges can be calculated as +1.8×10⁻² N and its repulsive.

To find the electrical force, distance = 2 meters

charge q1 = 2×10⁻⁶ C

charge q2 = 4×10⁻⁶ C

<h3>Define coulomb's law and solve with formula.</h3>

The force of attraction or repulsion acting along a straight line between two electric charges is directly proportional to the product of the charges and inversely to the square of the distance between them.

Formula can be written as,

F = K ( q1q2 / r² )

F - electric force

k - Coulomb constant

q1, q2 - charges

r - distance of separation

Substituting the values in the formula,

F = 9 × 10⁹ Nm²/C² ( (2×10⁻⁶ C × 4×10⁻⁶ C) / (2²))

= 0.0179751

F = 1.8 × 10 ⁻² N.

As both the charges q1 and q2 are positive, the charges gets repulsive.

SO, the correct answer is Option A.

Learn more about coulomb's law,

brainly.com/question/506926

#SPJ1

8 0

2 years ago

The first-order decomposition of cyclopropane has a rate constant of 6.7 × 10–4 s–1. If the initial concentration of cyclopropan

Ket [755]

Answer:

.864 M

Explanation:

For first order decomposition,

rate constant k = 1/t x ln a / (a - x )

given , a = 1.33 M , t = 644 s , k = 6.7 x 10⁻⁴ , a - x = ? = b( let )

6.7 x 10 ⁻⁴ = 1/644 x ln 1.33/b

ln 1.33/b = 6.7 x 10⁻⁴ x 644 = .4315

1.33 / b = e⁰ ⁴³¹⁵ = 1.5395

b = 1.33 / 1.5395 = .864 M.

7 0

4 years ago