Answer:
Given: V = 220V, Pmin = 360W, Pmax = 840W
For minimum heating case:
We know that
Pmin = VI
360 = 220 X I
I = 1.63 amp
R = V/I
R = 220/1.63
R = 134.96ohms
For maximum heating case:
We know that
Pmax = VI
840 = 220 X I
I = 3.81 amp
R = V/I
R = 220/3.81
R = 57.74 ohms
Answer:
The SI was and is intended to extend and refine the definitions used by the MKS.
Answer:
speed when the block had slid 3.40 m is 2.68 m/s
Explanation:
given data
distance = 6.80 m
speed = 3.80 m/s
to find out
speed when the block had slid 3.40 m
solution
we will apply here equation of motion that is
v²-u² = 2×a×s ..............1
here s is distance, a is acceleration and v is speed and u is initial speed that is 0
so put here all value in equation 1 to get a
v²-u² = 2×a×s
3.80²-0 = 2×a×6.80
a = 1.06 m/s²
so
speed when distance 3.40 m
from equation 1 put value
v²-u² = 2×a×s
v²-0 = 2×1.06×3.40
v² = 7.208
v = 2.68
so speed when the block had slid 3.40 m is 2.68 m/s
C according to my calculations
That's 'centripetal acceleration'. It points toward the center of the circle in which the object is traveling, even if it's only a temporary piece of a circle.
