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Nostrana [21]
2 years ago
15

4. How does nearness to water affect the climate zone of an area?

Physics
2 answers:
lisov135 [29]2 years ago
8 0
I think the answer is A
Afina-wow [57]2 years ago
6 0

Answer:

Choice A.

Nearness to a body of water causes an increase in humidity, due to the higher rate of evaporation.

You might be interested in
What creates the energy of the Sun?
Svet_ta [14]

Answer:

C

Explanation:

During nuclear fusion, the high pressure and temperature in the sun's core cause nuclei to separate from their electrons. Hydrogen nuclei fuse to form one helium atom.

5 0
2 years ago
Topic: Chapter 10: Projectory or trajectile?
Charra [1.4K]

Answer:

The other angle is 75⁰

Explanation:

Given;

velocity of the projectile, v = 10 m/s

range of the projectile, R = 5.1 m

angle of projection, 15⁰

The range of a projectile is given as;

R = \frac{u^2sin(2\theta)}{g}

To find another angle of projection to give the same range;

5.1 = \frac{10^2 sin(2\theta)}{9.81} \\\\100sin(2\theta) = 50\\\\sin(2\theta) = 0.5\\\\2\theta = sin^{-1}(0.5)\\\\2\theta = 30^0\\\\\theta = 15^0\\\\since \ the \ angle \ occurs \ in \ \ the \ first \ quadrant,\  the \ equivalent \ angle \\ is \ calculated \ as;\\\\90- \theta = 15^0\\\\\theta = 90 - 15^0\\\\\theta = 75^0

<u>Check: </u>

sin(2θ) = sin(2 x 75) = sin(150) = 0.5

sin(2θ) = sin(2 x 15) = sin(30) = 0.5

5 0
2 years ago
A conductor of radius r, length and resistivity ρ has resistance r. what is the new resistance if it is stretched to 4 times its
max2010maxim [7]
The resistance of a conductor is given by
R= \frac{\rho L}{A}
where L is the length of the wire, \rho the resistivity of the material and A the cross-sectional area.

We can see that if all the other quantities do not change, if the new length of the conductor is 4 times the original length: L'=4 L, then the new resistance is also 4 times the original value:
R'= \frac{\rho L'}{A}= \frac{\rho 4 L}{A}=4  \frac{\rho L}{A}=4 R
7 0
3 years ago
(a) A long, straight solenoid has N turns, uniform cross-sectional area A, and length l. Show that the inductance of this soleno
Paul [167]

Answer:

a. L = μ₀AN²/l b. 1.11 × 10⁻⁷ H

Explanation:

a. The magnetic flux through the solenoid, Ф = NAB where N = number of turns of solenoid, A = cross-sectional area of solenoid and B = magnetic field at center of solenoid = μ₀ni where μ₀ = permeability of free space, n = number of turns per unit length = N/l where l = length of solenoid and i = current in solenoid.

Also, Li = Ф where L = inductance of solenoid.

So, Li = NAB

= NA(μ₀ni)

= NA(μ₀Ni/l)

Li = μ₀AN²i/l

dividing both sides by i, we have

So, L = μ₀AN²/l

b. The self- inductance, L = μ₀AN²/l where

A = πd²/4 where d = diameter of solenoid = 0.150 cm = 1.5 × 10⁻³ m, N = 50 turns, μ₀ = 4π × 10⁻⁷ H/m and l = 5.00 cm = 5 × 10⁻² m

So, L = μ₀AN²/l

L = μ₀πd²N²/4l

L = 4π × 10⁻⁷ H/m × π(1.5 × 10⁻³ m)²(50)²/(4 × 5 × 10⁻² m)

L = 11,103.3 × 10⁻¹¹ H

L = 1.11033 × 10⁻⁷ H

L ≅ 1.11 × 10⁻⁷ H

6 0
3 years ago
Julian and Joshua each maintain a constant speed as they run laps around a 400-meter track. In the time it takes Julian to compl
Marysya12 [62]

Answer:

the time Joshua travels 1 mile is 12.5 min

Explanation:

Let's start by finding the distance traveled on each lap,

Let's reduce everything to the SI system

    R = 400 m

    d = 1 mile (1609 m / 1 mile) = 1609 m

    L = 2 pi R

    L = 2 pi 400

    L = 2513 m

Let us form a rule of proportions if 2 turns of Julian is 3 turns Joshua, for 1 turn of Joshua how many turns Julian took

    lap Julian = 2/3 turn Joshua

Let's calculate what distance is the same for both of them since they are on the same track

    1 lap = 2513 m

    d. Julian = 2/3 2513 m

    d Julian = 1675 m distance Joshua

Let us form the last rule of three or proportions if 1609 m you travel in 12 min how long it takes to travel 1675 m

    t Julian = 1675/1609 12

    t = 12.5 s

Since this is the distance Joshua travels, this is the time Joshua travels 1 mile

5 0
3 years ago
Read 2 more answers
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