<span>Multiply one of the equations so that both equations share a common complementary coefficient.
In order to solve using the elimination method, you need to have a matching coefficient that will cancel out a variable when you add the equations together. For the 2 equations given, you have a huge number of choices. I'll just mention a few of them.
You can multiply the 1st equation by -2/5 to allow cancelling the a term.
You can multiply the 1st equation by 5/3 to allow cancelling the b term.
You can multiply the 2nd equation by -2.5 to allow cancelling the a term.
You can multiply the 2nd equation by 3/5 to allow cancelling the b term.
You can even multiply both equations.
For instance, multiply the 1st equation by 5 and the second by 3. And in fact, let's do that.
5a + 3b = –9
2a – 5b = –16
5*(5a + 3b = -9) = 25a + 15b = -45
3*(2a - 5b = -16) = 6a - 15b = -48
Then add the equations
25a + 15b = -45
6a - 15b = -48
=
31a = -93
a = -3
And then plug in the discovered value of a into one of the original equations and solve for b.</span>
Answer:
I do
Step-by-step explanation:
not know
Answer:
3.2.2.2.2...
Step-by-step explanation:
The prime factors of 96 are written as 2 x 2 x 2 x 2 x 2 x 3 or 3 x 25, where 2 and 3 are the prime numbers
Mass of electron:9.109 times 10^-31 kg
mass of proton: 1.673 times 10-27
speed of light=3.0 times 10^8
avogadro's number 6.02 times 10^32
planck's constant: 6.63 times 10^-34
just google chem constants sheet
Find the area of the square first
Area = Length x Width
Area = 12 x 9
Area = 108
Find the area of the right triangles
Area = 1/2(Length x Base)
Area = 1/2(9 x 2)
Area = 1/2(18)
Area = 9
Since there is 2 triangles multiply by 2
9 x 2 = 18
Now add
108 + 18 = 126
126 is your area
