Yes because the y intercept would be a different value for the new equation unless it is zero
Answer: 300 m
<u>Step-by-step explanation:</u>


= 150 + 150
= 300
Alright, so the distance formula is sqrt((x1-x2)^2+(y1-y2)^2), and plugging that in, we get sqrt((0-3)^2+(3-10)^2)=sqrt((-3)^2+(-7)^2)=sqrt(9+49)=sqrt(58)=around 7.6
Answer:
THREE HOURS
Step-by-step explanation:
34.50-12=22.5
22.5/7.50=
=3
Answer:
I think it's true
Step-by-step explanation:
if wrong I'm sorry