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nlexa [21]
3 years ago
9

Input divided by two plus one is the output

Mathematics
1 answer:
Naily [24]3 years ago
3 0
The equation to this problem would be y = x/2 + 1
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3/5 TIMES 1/2 WHOEVER ANSWERES IN UNDER 2 MINUTS I WILL MARK BRAINLIEST AND ILL GIVE YOU EXTRA POINTS
Ostrovityanka [42]

Step-by-step explanation:

3/10 or 0.3

hope it helps:))!

3 0
3 years ago
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2 Select the correct answer. Consider functions f and g. Which statement gives the best approximation of the solutions of the eq
kaheart [24]
  • Answer: are c and d

Step-by-step explanation: I think not sure.

6 0
2 years ago
Help pleaseeeeeeeee​
Doss [256]

Answer:9

Step-by-step explanation: im not really sure I kinda just guess and check, so like, 2/3 times 3 is 6/3 which is 2. so 6/2 is 3. 3 times 3 is nine.

4 0
3 years ago
A study indicates that 37% of students have laptops. You randomly sample 30 students. Find the mean and the standard deviation o
Brilliant_brown [7]

Answer:

The mean and the standard deviation of the number of students with laptops are 1.11 and 0.836 respectively.

Step-by-step explanation:

Let <em>X</em> = number of students who have laptops.

The probability of a student having a laptop is, P (X) = <em>p</em> = 0.37.

A random sample of <em>n</em> = 30 students is selected.

The event of a student having a laptop is independent of the other students.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The mean and standard deviation of a binomial random variable <em>X</em> are:

\mu=np\\\sigma=\sqrt{np(1-p)}

Compute the mean of the random variable <em>X</em> as follows:

\mu=np=30\times0.37=1.11

The mean of the random variable <em>X</em> is 1.11.

Compute the standard deviation of the random variable <em>X</em> as follows:

\sigma=\sqrt{np(1-p)}=\sqrt{30\times0.37\times(1-0.37)}=\sqrt{0.6993}=0.836

The standard deviation of the random variable <em>X</em> is 0.836.

5 0
3 years ago
Helppp<br><br><br> 20x-60/2=10(2x+4)
ikadub [295]

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THANK YOU.

7 0
3 years ago
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