Answer:
D. ![2NaBr + Cl_2\rightarrow 2NaCl + Br_2](https://tex.z-dn.net/?f=2NaBr%20%2B%20Cl_2%5Crightarrow%202NaCl%20%2B%20Br_2)
Explanation:
Hello!
In this case, for the given set of chemical reactions, it is possible to infer that D. is a categorized as redox due to the following:
Since both chlorine and bromine remain as diatomic gases, their oxidation states in such a form is 0, but as anions with lithium cations they have a charge of - according to the following reaction and half-reactions:
![2NaBr + Cl_2\rightarrow 2NaCl + Br_2](https://tex.z-dn.net/?f=2NaBr%20%2B%20Cl_2%5Crightarrow%202NaCl%20%2B%20Br_2)
![Cl_2^0+2e^-\rightarrow 2Cl ^-\\\\2Br^- \rightarrow Br_2^0+2e^-](https://tex.z-dn.net/?f=Cl_2%5E0%2B2e%5E-%5Crightarrow%202Cl%20%5E-%5C%5C%5C%5C2Br%5E-%20%5Crightarrow%20%20Br_2%5E0%2B2e%5E-)
Unlike the other reactions whereas no change in the oxidation states is evidenced.
The options for given question are as follow,
1) Methane molecules show hydrogen bonding.
<span>2) Ammonia molecules show hydrogen bonding. </span>
<span>3) Methane has stronger hydrogen bonding than ammonia. </span>
<span>4) Both the compounds do not show hydrogen bonding. </span>
<span>5) Both the compounds have strong hydrogen bonding.
</span>
Answer:
Correct answer is Option-2 (Ammonia molecules show hydrogen bonding).
Explanation:
Hydrogen bond interactions are formed when a partial positive hydrogen atom attached to most electronegative atom of one molecule interacts with the partial negative most electronegative element of another molecule. So, in Ammonia hydrogen gets partial positive charge as nitrogen is highly electronegative. While the C-H bond in Methane is non-polar and fails to form hydrogen bond interactions.
Th first one is Iron and the second one is Xenon