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Evgen [1.6K]
3 years ago
13

Magnesium has three naturally occurring isotopes. The most common, magnesium-24, accounts for nearly 80% of the magnesium found

in nature. The atomic numbers and mass numbers for four different atoms are shown in the table below. Which of these atoms could be an isotope of magnesium?
Chemistry
1 answer:
Hitman42 [59]3 years ago
7 0

Answer : There are mainly three isotopes of magnesium found in nature; namely Mg-24, Mg-25 and Mg-26. Out of which Mg-24 has 12 neutrons, Mg-25 has 13 neutrons and Mg-26 has 14 neutrons in their atoms. The number of protons and their atomic masses remains the same for the atom. The relative abundance in nature differs for all the three isotopes. Mg-24 has abundance nearly 80% in nature, Mg-25 has abundance as 10% and Mg-26 has 11.01% abundance.

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Which biogeochemical cycle is the only one that does not include the atmosphere?
In-s [12.5K]

Answer:

Phosphorus cycle

Explanation:

Biogeochemical cycle, any of the natural pathways by which essential elements of living matter are circlated.

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6 0
3 years ago
Which factor most influenced the economic
Vikki [24]

It was by far "warm and wet growing seasons" that was the most important factor in terms of the South's economic development. Cotton and tobacco were the biggest exports.

Explanation:

These crops created tons of cash, had massive markets round the world, however required a stable and enormous hands to grow and harvest them.The yank South is understood for its long, hot summers, and wealthy soils in stream valleys creating it a perfect location for growing cotton. the various southern seaports and riverside docks allowed shipping cotton to remote destinations. By 1860, Southern plantations equipped seventy fifth of the world's cotton, with shipments from Houston, city, Charleston, Mobile, Savannah, and some different ports. The unquenchable European demand for cotton was a results of the commercial Revolution that created the machinery and factories to method raw cotton into vesture that was higher and cheaper than hand-made product.

6 0
3 years ago
Read 2 more answers
At equilibrium, the concentrations of the products and reactants for the reaction, H2 (g) + I2 (g)  2 HI (g), are [H2] = 0.106
lana [24]

Answer:

The new equilibrium concentration of HI: <u>[HI] = 3.589 M</u>          

Explanation:

Given: Initial concentrations at original equilibrium- [H₂] = 0.106 M; [I₂] = 0.022 M; [HI] = 1.29 M        

Final concentrations at new equilibrium- [H₂] = 0.95 M; [I₂] = 0.019 M; [HI] = ? M

<em>Given chemical reaction:</em> H₂(g) + I₂(g) → 2 HI(g)

The equilibrium constant (K_{c}) for the given chemical reaction, is given by the equation:

K_{c} = \frac {[HI]^{2}}{[H_{2}]\: [I_{2}]}

<u><em>At the original equilibrium state:</em></u>

K_{c} = \frac {(1.29\: M)^{2}}{(0.106\: M) \times (0.022\: M)}

K_{c} = \frac {1.6641}{0.002332} = 713.59

<u><em>Therefore, at the new equilibrium state:</em></u>

K_{c} = \frac {[HI]^{2}}{(0.95\: M) \times (0.019\: M)}

\Rightarrow K_{c} = 713.59 = \frac {[HI]^{2}}{0.01805}

\Rightarrow [HI]^{2} = 713.59 \times 0.01805 = 12.88

\Rightarrow [HI] = \sqrt {12.88} = 3.589 M

<u>Therefore, the new equilibrium concentration of HI: [HI] = 3.589 M</u>

6 0
2 years ago
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