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Anna71 [15]
3 years ago
7

Identify this reaction.

Chemistry
1 answer:
MakcuM [25]3 years ago
6 0
<h3>Answer:</h3>

Single displacement reaction

<h3>Explanation:</h3>
  • Single replacement reaction is a type of reaction in which a reactive element displaces a less reactive element from its compound.
  • The reaction given above; Al + H₂SO₄ → Al₂(SO₄)₃ + H₂ is a single replacement reaction.
  • This is because Aluminium takes the place of hydrogen atoms in sulfuric acid to form aluminium sulfate and hydrogen gas.
  • Double replacement reaction is where cations or anions are exchanged between two compounds to form new compounds.
  • For example the reaction; NaCl(aq) + AgNO₃(aq) → NaNO₃(aq) + AgCl(aq) is a double displacement reaction.
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In an electrically heated boiler, water is boiled at 140°C by a 90 cm long, 8 mm diameter horizontal heating element immersed in
RideAnS [48]

Explanation:

The given data is as follows.

Volume of water = 0.25 m^{3}

Density of water = 1000 kg/m^{3}

Therefore,  mass of water = Density × Volume

                       = 1000 kg/m^{3} \times 0.25 m^{3}

                       = 250 kg  

Initial Temperature of water (T_{1}) = 20^{o}C

Final temperature of water = 140^{o}C

Heat of vaporization of water (dH_{v}) at 140^{o}C  is 2133 kJ/kg

Specific heat capacity of water = 4.184 kJ/kg/K

As 25% of water got evaporated at its boiling point (140^{o}C) in 60 min.

Therefore, amount of water evaporated = 0.25 × 250 (kg) = 62.5 kg

Heat required to evaporate = Amount of water evapotaed × Heat of vaporization

                           = 62.5 (kg) × 2133 (kJ/kg)

                           = 133.3 \times 10^{3} kJ

All this heat was supplied in 60 min = 60(min)  × 60(sec/min) = 3600 sec

Therefore, heat supplied per unit time = Heat required/time = \frac{133.3 \times 10^{3}kJ}{3600 s} = 37 kJ/s or kW

The power rating of electric heating element is 37 kW.

Hence, heat required to raise the temperature from 20^{o}C to 140^{o}C of 250 kg of water = Mass of water × specific heat capacity × (140 - 20)

                      = 250 (kg) × 40184 (kJ/kg/K) × (140 - 20) (K)

                     = 125520 kJ  

Time required = Heat required / Power rating

                       = \frac{125520}{37}

                       = 3392 sec

Time required to raise the temperature from 20^{o}C to 140^{o}C of 0.25 m^{3} water is calculated as follows.

                    \frac{3392 sec}{60 sec/min}

                     = 56 min

Thus, we can conclude that the time required to raise the temperature is 56 min.

4 0
3 years ago
If 13.8 moles of carbon (c), with a density of 2.26 g/ml, are needed for a chemical reaction, how many milliliters of carbon are
charle [14.2K]

13.8 moles of carbon = 12 g/mol*13.8 or 165.6 grams

165.6 grams/ 2.26 g/mL = 73.27434 or 73.3 mL


I hope this helps!!!!


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3 years ago
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What are the tube feet on a star fish
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They are used to pass food to the oral mouth at the center, and can attach to surfaces.
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Describe at least two methods to separate a mixture of small copper and iron beads
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<span>A fast way to separate the mixture would be to use a magnet. Iron is magnetic while copper is not. The second method would be to visually separate them since iron and copper distinctly different colors.</span>
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How many atoms are in 0.100 mol of C3H8
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Number of atoms = mole x Avogadro’s Number

= 0.1 x 6.022 x 10^23
= 6.022 x 10^22
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