Answer:
its the first one in the 3p section mf
Explanation:
Answer: True
Explanation:
Titration is a quantitative technique where a solution of known concentration is used to determine the concentration of an unknown solution. The titrant (the known solution) is added from a burette to a known quantity of the the unknown solution until the reaction is complete.
By knowing the volume of titrant, we can determine the concentration of the unknown.
Thus the statement Titrations provide a method of quantitatively measuring the concentration of an unknown solution is True .
Answer:
Explanation:
Sn + 2HBr = SnBr₂ + H₂
Here HBr is an acid but Sn is not a base . It is a metal . So it is not an acid - base reaction .
HCl + KOH = KCl + H₂O
HCl is an acid and KOH is a base so it is an acid base reaction.
2AlCl₃ + 3Ca(OH)₂ = 2Al(OH)₃ + 3CaCl₂
It is an acid base reaction . It is so because aluminium hydroxide is a lewis acid and calcium hydroxide is a base . So it is an acid base reaction .
2C₂H₆ +7O₂ = 4CO₂ + 6H₂O
It is not an acid base reaction . It is actually an example of oxidation reaction in which ethane burns in oxygen to give carbon dioxide and water.
Answer:
Using the Iodoform test, we can differentiate both compounds.
Explanation:
Benzaldehyde (C6H5CHO -an aldehyde) and Acetophenone (C6H5COCH3 - a methyl ketone) can be differentiated by reacting both compounds with iodine in a basic (NaOH) solutions.
The methyl ketone (acetophenone) gives a pale yellow precipitate of triiodomethane (iodoform) while the aldehyde (benzaldehyde) would not react.
This is known as the IODOFORM test and is indicative for methyl ketones
Answer:
Volume of HNO₃ required = 140 mL
Explanation:
Given data:
Molarity of HNO₃ = 0.563 M
mass of BaCO₃ = 7.83 g
Volume of HNO₃ = ?
Solution:
First of all we will write the balance chemical equation
2HNO₃ + BaCO₃ → Ba(NO₃)₂ + H₂O + CO₂
Number of moles of BaCO₃ = mass / molar mass
Number of moles of BaCO₃ = 7.83 g / 197.34 g/mol
Number of moles of BaCO₃ = 0.04 mol
Now we compare the moles of BaCO₃ and HNO₃ .
BaCO₃ : HNO₃
1 : 2
0.04 : 2×0.04 = 0.08 mol
Volume of HNO₃ required = number of moles / Molarity
Volume of HNO₃ required = 0.08 mol / 0.563 mol/L
Volume of HNO₃ required = 0.14 L
0.14 × 1000 = 140 mL
