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RoseWind [281]
4 years ago
9

What is the mass of an atom that has 4 protons, 5 neutrons, and 4 electrons?

Chemistry
2 answers:
Mazyrski [523]4 years ago
3 0
The answer would be 9
WITCHER [35]4 years ago
3 0
To get the mass, you would add the <span> 4 protons and 5 neutrons so it would be 9. 
(The electrons weigh practically nothing so you just ignore them.)</span>
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Read 2 more answers
What is the pH if 1mL of 0.1M HCl is added to 99mL of pure water?
coldgirl [10]

Answer:

pH of buffer after addition of 1 mL of 0,1 M HCl = 7,0

Explanation:

It is possible to use Henderson–Hasselbalch equation to estimate pH in a buffer solution:

pH = pka + log₁₀

Where A⁻ is conjugate base and HA is conjugate acid

The equilibrium of phosphate buffer is:

H₂PO₄⁻ ⇄ HPO4²⁻ + H⁺    Kₐ₂ = 6,20x10⁻⁸; pka=7,2

Thus, Henderson–Hasselbalch equation for 7,00 phosphate buffer is:

7,0 = 7,2 + log₁₀ \frac{[HPO4^{2-}] }{[H2PO4^{-}]}

Ratio obtained is:

0,63 = \frac{[HPO4^{2-}] }{[H2PO4^{-}]}

As the problem said you can assume [H₂PO₄⁻] = 0,1 M and [HPO4²⁻] = 0,063M

As the amount added of HCl is 0,001 M the concentrations in equilibrium are:

H₂PO₄⁻   ⇄   HPO4²⁻ +        H⁺

0,1 M +x      0,063M -x  0,001M -x -<em>because the addition of H⁺ displaces the equilibrium to the left-</em>

Knowing the equation of equilibrium is:

K_{a} = \frac{[HPO_{4}^{2-}][H^{+}]}{[H_{2} PO_{4}^{-}]}

Replacing:

6,20x10⁻⁸ = \frac{[0,063-x][0,001-x]}{[0,1+x]}

You will obtain:

x² -0,064 x + 6,29938x10⁻⁵ = 0

Thus:

x = 0,063 → No physical sense

x = 0,00099990

Thus, [H⁺] in equilibrium is:

0,001 M - 0,00099990 = 1x10⁻⁷

Thus, pH of buffer after addition of 1 mL of 0,1 M HCl =

-log₁₀ [1x10⁻⁷] = 7,0

A buffer is a solution that can resist pH change upon the addition of an acidic or basic components. In this example you can see its effect!

I hope it helps!

5 0
3 years ago
If the (H+) is 2.1×10^-12 MHCIO4, What is the PH? is the solution ACIDIC, BASIC or NEUTRAL.​
Lilit [14]

Explanation:

The pH of a substance can be found by using the formula

pH =  -  log[ H^{ + }  ]

where [ H+ ] is the hydrogen ion concentration in the substance

From the question

[ H+ ] = 2.1 × 10-¹² M

To find the pH substitute the value into the above formula

We have

pH =  -  log(2.1 \times  {10}^{ - 12} )  \\  = 11.6777807 \:  \:  \:  \:  \:  \:

We have the answer as

<h2>pH = 11.7 </h2>

The solution is basic since it lies in the basic region that is from 8 to 14

Hope this helps you

8 0
3 years ago
The physical state of CaBr2 at room temperature? Predict the two other properties of CaBr2 Deduce the charge of ion Ca in the co
Fofino [41]

Answer:

CaBr2 is a colorless solid and the charge on Calcium is +2

Explanation:

CaBr2 is a colorless solid at room temperature.

Other properties include -

a) It is a crystalline solid

b) Melting point of 765°C.

c) It is deliquescent

d) Soluble in water and absolute alcohol.

The charge of Br is -1. Here two atoms of Br attaches with one atom of calcium. Hence the charge of calcium is +2

7 0
3 years ago
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