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3 years ago

Calculate the relative atomic mass of M

Chemistry

1 answer:

aalyn [17]3 years ago

7 0

Answer:

63.55

Explanation:

relative atomic mass=(mass of isotope1×relative abundance)+(mass of isotope 2×relative abundance)/100

r.a.m=(62.93×69.09)+(64.93×30.91)/100

=(4347.8337)+(2006.9863)/100

=6354.82/100

=63.55

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3 years ago

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3 years ago

How many molecules of carbon dioxide are in 5.61 moles of carbon dioxide (CO2)?

gulaghasi [49]

<h3>Answer:</h3>

3.38 × 10²⁴ molecules CO₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 5.61 moles CO₂

[Solve] molecules CO₂

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

[DA] Set up: $\displaystyle 5.61 \ mooles \ CO_2(\frac{6.022 \cdot 10^{23} \ molecules \ CO_2}{1 \ mol \ CO_2})$
[DA] Multiply/Divide [Cancel out units]: $\displaystyle 3.37834 \cdot 10^{24} \ molecules \ CO_2$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

3.37834 × 10²⁴ molecules CO₂ ≈ 3.38 × 10²⁴ molecules CO₂

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3 years ago