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mariarad [96]
3 years ago
6

Which of the following is right?

Physics
1 answer:
barxatty [35]3 years ago
7 0
Scientific theory because it's a theory it's already an answer but it might change depending on the condition.
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A 0.58 kg mass is moving horizontally with a speed of 6.0 m/s when it strikes a vertical wall. The mass rebounds with a speed of
Sunny_sXe [5.5K]

Answer:

5.8\; {\rm kg\cdot m \cdot s^{-1}}.

Explanation:

If the mass of an object is m and the velocity of that object is v, the linear momentum of that object would be m\, v.

Assume that the initial velocity of the mass is positive (6.0\; {\rm m\cdot s^{-1}}.) However, the direction of the velocity is reversed after the impact. Thus, the sign of the new velocity of the object would be negative- the opposite of that of the initial velocity. The new velocity would be (-4.0\; {\rm m\cdot s^{-1}}).

Thus, the change in the velocity of the mass would be:

\begin{aligned}& (\text{Change in Velocity}) \\ =\; & (\text{Final Velocity}) - (\text{Initial Velocity}) \\ =\; & (-4.0\; {\rm m\cdot s^{-1}}) - (6.0\; {\rm m\cdot s^{-1}}) \\ =\; & (-10\; {\rm m\cdot s^{-1})\end{aligned}.

The change in the linear momentum of the mass would be:

\begin{aligned} & \text{change in momentum} \\ =\; & (\text{mass}) \times (\text{change in velocity}) \\ =\; & 0.58\; {\rm kg} \times (-10\; {\rm m\cdot s^{-1}}) \\  =\; & (-5.8\; {\rm kg \cdot m \cdot s^{-1}})\end{aligned}.

Thus, the magnitude of the change of the linear momentum would be 5.8\; {\rm kg \cdot m \cdot s^{-1}}.

7 0
2 years ago
Heyyy! Okay riddle of the day
vekshin1

Answer:

Time to get a new fence...?

C'mon that's pretty cringe lol

Please give brainliest

have a nice day :D

3 0
3 years ago
Jeremy walked at an average rate of speed of 5 km/h. how far had Jeremy walked in 15 minutes?
astraxan [27]

Answer:

1 half kilometer is right answer

5 0
3 years ago
Read 2 more answers
Some enterprising physics students working on a catapult decide to have a water balloon fight in the school hallway. The ceiling
sergejj [24]

Answer:

\alpha =54.7º

Explanation:

From the exercise we have our initial information

y=3.4m\\v_{o}=10m/s\\g=-9.8m/s^2

When the balloon gets to the ceiling its velocity at that moment is 0 m/s. Being said that we can calculate velocity at the vertical direction

v_{y}^2=v_{oy}^2+ag(y-y_{o})

Since v_{y}=0 and y_{o}=0

0=v_{oy}^2-2(9.8m/s^2)(3.4m)

v_{oy}=\sqrt{2(9.8m/s^2)(3.4m)}=8.16m/s

Knowing that

v_{oy}=v_{o}sin\alpha

sin\alpha =\frac{v_{oy} }{v_{o} }

\alpha =sin^{-1}(\frac{v_{oy}}{v_{o}})=sin^{-1}(\frac{8.16m/s}{10m/s})=54.7º

8 0
3 years ago
A string fixed at both ends is 8.40 m long and has a mass of 0.120 kg. It is subjected to a tension of 96.0 N and set oscillatin
Luden [163]

Answer:

81.9756 m/s

16.8 m

4.8795 Hz

Explanation:

m = Mass of string = 0.12 kg

L = Length of string = 8.4 m

T = Tension on string = 96 N

Linear density is given by

\mu=\dfrac{m}{L}\\\Rightarrow \mu=\dfrac{0.12}{8.4}

Spee of the wave is given by

v=\sqrt{\dfrac{T}{\mu}}\\\Rightarrow v=\sqrt{\dfrac{96}{\dfrac{0.12}{8.4}}}\\\Rightarrow v=81.9756\ m/s

The speed of the waves on the string is 81.9756 m/s

Wavelength is given by

\lambda=2L\\\Rightarrow \lambda=2\times 8.4\\\Rightarrow \lambda=16.8\ m

The longest possible wavelength is 16.8 m

Frequency is given by

f=\dfrac{v}{\lambda}\\\Rightarrow f=\dfrac{81.9756}{16.8}\\\Rightarrow f=4.8795\ Hz

The frequency of the wave is 4.8795 Hz

3 0
3 years ago
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