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12345 [234]
3 years ago
8

Momentum for a system can be conserved in one direction while not being conserved in another. What is the anglebetween the direc

tions? Give an example.
Physics
1 answer:
katrin [286]3 years ago
5 0

Answer:

90°

Explanation:

The angle will be 90° when momentum for a system can be conserved in one direction while not being conserved in another.

The example can be

If we apply force on an object horizontally in west direction, then as in other direction south or north we cannot apply the principal of momentum conservation.

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A particle in circular motion performs 30 oscillation in 6 seconds. what is it angular velocity​
sp2606 [1]

Explanation:

ω = 30 rev × (2π rad/rev) / (6 sec)

ω = 10π rad/s

ω ≈ 31.4 rad/s

4 0
3 years ago
Gold is called noble gas why
slamgirl [31]
This is what i found.
Gold<span> is a </span>noble<span> element because "in chemistry, the </span>noble<span>metals are metals that are resistant to corrosion and oxidation in moist air (unlike most base metals)."</span>
3 0
4 years ago
Read 2 more answers
A net force of 25N causes an object to accelerate at 4m/s^2. what is the mass of the object?
Doss [256]

Answer:

6.25 kg

Explanation:

Fnet=ma

m=Fnet/a

m=25/4

m=6.25kg

3 0
3 years ago
21. An AC generator has an rms output voltage of 274 V at a frequency of 57.0 Hz.
maks197457 [2]

The answers are as follows;

a) the inductive reactance is 322 ohm

b) The maximum voltage is 387.5 V

c) The rms and maximum currents in the inductor are 1.2 A and 0.85 A.

<h3>What is the reactance?</h3>

The reactance is obtained from;

XL = 2πfL

XL = 2 * 3.14 * 57.0 * 0.900

XL = 322 ohm

The maximum voltage is obtained as;

Vo = Vrms * √2

Vo =  274 V * √2

Vo = 387.5 V

Io = Vo/XL

Io =  387.5 V/ 322 ohm

Io = 1.2 A

Irms = 274 V/322 ohm

Irms = 0.85 A

Learn more about inductive reactance:brainly.com/question/17129912

#SPJ1

4 0
2 years ago
The St. Louis Arch has a height of 192 m. Suppose that a stunt woman of mass 84 kg jumps off the top of the arch with an elastic
Hitman42 [59]

To solve this problem it is necessary to apply the kinematic equations of motion for speed and distance, as well as the concepts related to kinetic energy.

The change in the height of a body subject to gravity is given by

h = \frac{1}{2} gt^2 \rightarrow t = \sqrt{\frac{2h}{g}}

Where

h = Height

g =Gravity

t = time

Replacing with our values we have that the time is

t = \sqrt{\frac{2h}{g}}

t = \sqrt{\frac{2(192)}{9.8}}

t = 6.25s

From speed as a function of change between acceleration and time we have then that after 2.6 seconds the speed would be

g = \frac{v}{t} \rightarrow v = g*t

v = 9.8*2.6

v = 25.48m/s

The kinetic energy would be given by

KE = \frac{1}{2} mv^2

KE = \frac{1}{2} (84)(25.48)

KE = 1070.16J

Therefore the kinetic energy after 2.6s is 1070.16J

6 0
3 years ago
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