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12345 [234]
3 years ago
8

Momentum for a system can be conserved in one direction while not being conserved in another. What is the anglebetween the direc

tions? Give an example.
Physics
1 answer:
katrin [286]3 years ago
5 0

Answer:

90°

Explanation:

The angle will be 90° when momentum for a system can be conserved in one direction while not being conserved in another.

The example can be

If we apply force on an object horizontally in west direction, then as in other direction south or north we cannot apply the principal of momentum conservation.

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An 8-hour exposure to a sound intensity level of 90.0 dB may cause hearing damage. What energy in joules falls on a 0.800-cm-dia
11111nata11111 [884]

Answer:

1.4E-3J

Explanation:

Given that

Time = 8hrs = 28.8E3 seconds

Intensity= 90dB

D= 0.008m

Radius= 0.004m

So intensity is sound level Bis

10dBlog(I/Io)

I= 10 (B/10dB)Io

= 10( 90/10) x 10^-12

=0.001W/m²

But we know that

I = P/A

P= I πr²

= 5.02 x10^-8W

But energy is power x time

So E= 5.02E-8 x 28.8E3

= 1.4E-3J

5 0
3 years ago
Read 2 more answers
In the simplified version of Kepler's third law, P 2 = a3, the units of the orbital period P and the semimajor axis a of the ell
Orlov [11]

Answer:

The units of the orbital period P is <em>years </em> and the units of the semimajor axis a is <em>astronomical units</em>.

Explanation:

P² = a³ is the simplified version of Kepler's third law which governs the orbital motion of large bodies that orbit around a star. The orbit of each planet is an ellipse with the star at the focal point.

Therefore, if you square the year of each planet and divide it by the distance that it is from the star, you will get the same number for all the other planets.

Thus, the units of the orbital period P is <em>years </em> and the units of the semimajor axis a is <em>astronomical units</em>.

8 0
3 years ago
A power plant running at 39 % efficiency generates 330 MW of electric power. Part A At what rate (in MW) is heat energy exhauste
marusya05 [52]

516.154 megawatts of heat are <em>exhausted</em> to the river that cools the plant.

By definition of energy efficiency, we derive an expression for the energy rate exhausted to the river (Q_{out}), in megawatts:

Q_{out} = Q_{in} - W

Q_{out} = \left(\frac{1}{\eta}-1 \right)\cdot W(1)

Where:

  • \eta - Efficiency.
  • W - Electric power, in megawatts.

If we know that \eta = 0.39 and W = 330\,MW, then the energy rate exhausted to the river is:

Q_{out} = \left(\frac{1}{0.39}-1 \right)\cdot (330\,MW)

Q_{out} = 516.154\,MW

516.154 megawatts of heat are <em>exhausted</em> to the river that cools the plant.

We kindly to check this question on first law of thermodynamics: brainly.com/question/3808473

7 0
3 years ago
D) 2,5 dm3 =... cm3= .... ml =...cc<br>​
DerKrebs [107]
Hey can u give a little more detail?
6 0
3 years ago
Read 2 more answers
The battery charger for an mp3 player contains a step-down transformer with a turns ratio of 1:24, so that the voltage of 120 v
miskamm [114]
Considering that we are talking about a stepdown transformer, and a turn ration of 1:24

Then

Vsecondary coil = 120 V / 24 = 5V

(But lets remember that the power must be conserved in the transformer, so the voltage is 24 times less, but the current is 24 times higher)

It provides 5 volts to operate the player or charge the batteries
8 0
4 years ago
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