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Sav [38]
3 years ago
7

3. Sodium carbonate (Na2CO3) is formed from the reaction between

Chemistry
2 answers:
user100 [1]3 years ago
8 0

Na2C03 is formed through the reaction of

NaOH and H2CO3 namely sodium hydroxide and carbonic acid

NaOH -> strong base

H2CO3-> weak acid

mr_godi [17]3 years ago
5 0

Answer:

A. a weak acid and a strong base

Explanation:

An acid-base reaction is a chemical reaction between an acid and a base to form salt and water. The reaction is also known as a neutralization reaction.

An acid is a compound that when in aqueous solution it dissociate to form an hydrogen ion(H+).

A base is a compound that when in aqueous solution it produces an hydroxide ion(OH-) .

A strong acid is an acid that completely dissociate in an aqueous solution.

A strong base is a base that completely dissociate in an aqueous solution.

The reaction that produce a salt like sodium carbonate is a chemical reaction between a weak acid and a strong base. The chemical reaction can be represented as follows

H2CO3 + 2NaOH → Na2CO3 + 2H2O

H2CO3 is a weak acid as it partially dissociate in aqueous solution.

NaOH is a strong base as it completely dissociate in aqueous solution.

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7 Which of the following functional groups is present in an organic compound which gives bubbles on treatment with a saturated s
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Answer:

A. Carboxyl group

Explanation:

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6 0
3 years ago
Q8. The titration of 15.00 mL of HBr solution of unknown concentration requires 18.44 mL of a 0.100 M KOH solution to reach the
lara [203]

Answer: 0.123 M

Explanation:

According to the neutralization law:

n_1M_1V_1=n_2M_2V_2

where,

M_1 = molarity of HBr solution = ?

V_1 = volume of HBr solution = 15.00 ml

M_2 = molarity of KOH solution = 0.100 M

V_2 = volume of KOH solution = 18.44 ml

n_1 = valency of HBr = 1

n_2 = valency of KOH = 1

1\times M_1\times 15.00=1\times 0.100\times 18.44

M_1=0.123

Therefore, the concentration of the unknown HBr solution is 0.123 M

8 0
3 years ago
The chemical equation below shows the formation of aluminum oxide (Al2O3) from aluminum (Al) and oxygen (O2).
Rufina [12.5K]

Answer:

Mass = 182.4 g

Explanation:

Given data:

Number of moles of Al₂O₃ = 3.80 mol

Mass of oxygen required = ?

Solution:

Chemical equation:

4Al + 3O₂    →       2Al₂O₃

Now we will compare the moles of aluminum oxide and oxygen.

                Al₂O₃           :           O₂

                   2               :            3

                 3.80            :         3/2×3.80 = 5.7

Mass of oxygen:

Mass = number of moles × molar mass

Mass = 5.7 mol × 32 g/mol

Mass = 182.4 g

4 0
3 years ago
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