34.5 X 10^-11 grams of lead
Answer:
it's easier to lose one electron because it's less work for the atom to do and easier to lose one than gain a whole 7, because the atom wants to gain a full outer shell as soon as possible
Answer: The final temperature when heat in the amount of 800 kJ is added to 10 moles of ethylene initially at is .
Explanation:
It is known that the heat capacity of ethylene is 2.145 J/g K. Hence, for 10 moles of ethylene its mass will be as follows.
No. of moles =
10 mol =
mass = 280.5 g
Now, we know that relation between heat energy, mass and specific heat is as follows.
q =
1329.63 = T - 473
T = 1802.63 K
or, =
=
Thus, we can conclude that the final temperature when heat in the amount of 800 kJ is added to 10 moles of ethylene initially at is .
The electron domain geometry of all of the above except XeF4 (answer E) is a tetrahedral.
Explanation
Tetrahedral is a molecular shape that result when they are four bonds and no lone pair around the central atom in the molecule.
The bond bonded to the central atom lie at the corner of tetrahedron with 109.5 degrees between them.
CBr4,PH3 , CCl2Br2 has a tetrahedral geometry while XeF4 has a square planar.
Answer:
0.396 M
Explanation:
Let's consider the following reaction.
2 COF₂(g) ⇌ CO₂(g) + CF₄(g)
We can find the concentrations at equilibrium using an ICE Chart.
2 COF₂(g) ⇌ CO₂(g) + CF₄(g)
I 2.00 0 0
C -2x +x +x
E 2.00-2x x x
The concentration equilibrium constant (Kc) is:
The concentration of COF₂ at equilibrium is:
[COF₂] = 2.00-2x = 2.00-2(0.802) = 0.396 M