All categories

2 years ago

What is a measure of the consistency and stability of test scores when readministered at different times?

Physics

1 answer:

tino4ka555 [31]2 years ago

5 0

Answer:

Reliability is typically shown as a reliability coefficient created in a calculation to determine the reliability, or consistency, of scores, such as a measure of the amount of consistency between two sets of scores from different administrations from the same group of students.

You might be interested in

………………………….. yeah I know I was just looking looking at the guy that was like yeah yeah I know it’s crazy but ……………………..

Lelechka [254]

What..?

4x+5=13
13-5=8
8 divided by 4=2
Answer: x=2

7 0

2 years ago

Read 2 more answers

What does this mathematical expression mean? D 1/T

san4es73 [151]

The question is incomplete. If D=1/T then the answer is D, but if instead of =, there is a proportional sign, then the answer is C.

7 0

2 years ago

Read 2 more answers

If your weight is 120 pounds and your mass is 54 kilograms how would those values change if you were on the moon

BlackZzzverrR [31]

The gravitation acceleration on the moon is different than on Earth. It is 1.6 m/s^2. If you weigh 120 lbs, then you would multiply 120 pounds by the gravitational acceleration on the moon and then divide by the acceleration on Earth.

(120 lbs * 1.6) / 9.8 = 20 pounds.

The mass will always be the same no matter what planet you’re on, so it’s still 54 kg.

4 0

2 years ago

Help immediately! Answer I need help.

garri49 [273]

Answer:

0.80 m

Explanation:

elastic potential energy formula

elastic potential energy = 0.5 × spring constant × (extension) 2

4 0

2 years ago

What must be the length of a simple pendulum if its oscillation frequency is to be equal to that of an air-track glider of mass

Anvisha [2.4K]

Answer:

the length of the simple pendulum is 0.25 m.

Explanation:

Given;

mass of the air-track glider, m = 0.25 kg

spring constant, k = 9.75 N/m

let the length of the simple pendulum = L

let the frequency of the air-track glider which is equal to frequency of simple pendulum = F

The oscillation frequency of air-track glider is calculated as;

$F = \frac{1}{2\pi } \sqrt{\frac{k}{m} } \\\\F = \frac{1}{2\pi } \sqrt{\frac{9.75}{0.25} } \\\\F = 0.994 \ Hz$

The frequency of the simple pendulum is given as;

$F = \frac{1}{2\pi} \sqrt{\frac{g}{l} } \\\\2\pi(F) = \sqrt{\frac{g}{l} } \\\\2\pi (0.994) = \sqrt{\frac{9.8}{l} } \\\\6.2455 = \sqrt{\frac{9.8}{l} } \\\\(6.2455)2 = \frac{9.8}{l} \\\\39.006 = \frac{9.8}{l} \\\\l = \frac{9.8}{39.006} \\\\l = 0.25 \ m$

Thus, the length of the simple pendulum is 0.25 m.

8 0

2 years ago