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xeze [42]
3 years ago
5

Which stage of star development comes right after the long stable phase in the life cycle

Physics
1 answer:
Bond [772]3 years ago
6 0
I believe It's either a supernova or a planetary nebula.
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Can someone help me with this please?
shutvik [7]

Answer:

Your answer will be C. 3.8 kPa.

7 0
3 years ago
Select all that apply.
ElenaW [278]
Growing quickly

concentrated in a few areas

<span>putting pressure on resources and space</span>
4 0
3 years ago
why Galileo's thought experiment about the ball rolling forever on a level surface could only be a thought experiment.
erma4kov [3.2K]
Because in reality there are frictional forces acting on the ball, against the direction of its motion. In fact, because of the friction between the ball and the surface, the ball loses little by little its energy, so its velocity decreases and eventually it stops. 
In an ideal world with no friction, there would be no forces acting on the ball, so its energy must be conserved and this means that the ball would continue its motion forever.
8 0
4 years ago
A man is sitting on a chair. Identify the true scenario from the following options:
mote1985 [20]

Answer:

kinetic energy

Explanation:

3 0
3 years ago
The maximum speed with which you can throw a stone is about 25 m/s. Can you hit a window 50 m away and 13 m up from the point wh
Nookie1986 [14]

Answer:

no, the maximum height = 12.3m

Explanation:

The equation for the trajectory of the ball for a given angle can be derived from:

(1) x=cos\phi v_0t

and

(2) y=-\frac{1}{2}gt^2 +sin\phi v_0t

Combining equation 1 and 2:

(3) y=xtan\phi -\frac{gx^2}{2cos^2\phi v_0^2}

Taking the derivative:

(4) \frac{dy}{d\phi}=\frac{xsec^2\phi}{v_0^2}(v_0^2-gxtan\phi)

Setting equation 4 equal to zero to calculate the maximum angle:

(5) \phi=tan^{-1}(\frac{v_0^2}{gx})

Plugging equation 5 back into equation2 confirms, the trajectory can't reach the target. The maximum height is 12.3m.

3 0
3 years ago
Read 2 more answers
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