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Nitella [24]
3 years ago
11

A park in the shape of a right triangle is set in the middle of 3 square rose gardens, with one garden along each side. Which st

atement is true about the 3 gardens?
A) The area of Garden B minus the area of Garden C is equal to the area of Garden A.
B) The area of Garden B plus the area of Garden C is equal to twice the area of Garden A.
C) The area of Garden C minus the area of Garden B equals the area of Garden A.
D) The area of Garden C minus the area of Garden A is equal to twice the area of Garden B.

Mathematics
2 answers:
Sav [38]3 years ago
3 0
The answer would be C. This is because of Pythagorean theorem. A^2 + B^2=C^2 
Natali [406]3 years ago
3 0

Answer:

The area of Garden C minus the area of Garden B equals the area of Garden A.

Thus, (C) is the correct option.      

Step-by-step explanation:

In the figure below, PQR is a right angle triangle with right angle at R and A is perpendicular , B is base and C is hypotenuse  of the triangle.

One square garden along  each side of triangle.

Area of square = Side × Side

So area of each square garden is :

A × A = A²

B × B = B²

C × C = C²

According to Pythagoras theorem,

In  a right angle triangle, square of hypotenuse is equal to  sum of square of the remaining two sides.

By figure,

A² + B² = C²

Area of garden A + area of garden B = Area of garden C

A² =  C² -B²

The area of Garden C minus the area of Garden B equals the area of Garden A.

Thus, (C) is the correct option.      

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<h3>What is the center of mass.?</h3>

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\begin{|c|c|} Masses \ & \ \ \ \ \ \ \ \ \ \ \ \ \ \ Located at \\\rho=x^{3}+x \cdot e^{-x} & \ \  \ \  x \in(0,1)$ \\\end

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