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attashe74 [19]
3 years ago
5

Dimensional formula of elasticity​

Physics
1 answer:
daser333 [38]3 years ago
7 0
The dimensional formula of elasticity would be [ML^-1T^-2]
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Como se representa un intervalo de tiempo
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Which of the following does not describe a scientific theory?
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The perceived pitch of a tone is largely determined by its
soldier1979 [14.2K]

The perceived pitch of a tone is largely determined by its frequency

<h3>What is  frequency ?</h3>

The frequency of a repeated event is its number of instances per unit of time. In some cases, it is also referred to as temporal frequency or ordinary frequency to underline differences with spatial and angular frequencies, respectively. One (event) per second is equal to one hertz (Hz), which is how frequency is stated.

The period is the reciprocal of the frequency since it is the length of time for one cycle in a repeating occurrence. If a heart beats 120 times per minute (2 hertz), for instance, its period, T—the space between beats—is half a second. In science and engineering, frequency is a crucial metric for describing the temporal rate of change seen in oscillatory systems.

To learn more about frequency  from the given link:

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3 0
2 years ago
Light travels at a speed of 3.00 x 10^11 cm/s. What is the speed of light in kilometers/hour?
rewona [7]

As 1 km = 1000 m = 1000,00 cm,

So, 1 cm = (1/1000,00) km

1 hour = 60 × 60 s = 3600 s

So,  1 s = (1 / 3600) hour

The light travels at a speed of 3.00 \times 10^{11}  \ cm/s.

In kilometer/hour,

3.00 \times 10^{11}  \ cm/s = 3.00 \times 10^{11} \frac{(1/1000,00) km}{ (1 / 3600) hour} = 108 \times 10^8 \ km/hour


4 0
4 years ago
A uniform thin rod of length 0.11 m and mass 4.6 kg can rotate in a horizontal plane about a vertical axis through its center. T
ale4655 [162]

Answer:

Explanation:

This problem is based on conservation of rotational momentum.

Moment of inertia of rod about its center

= 1/12 m l² , m is mass of the rod and l is its length .

= 1 / 12 x 4.6 x .11²

I = .004638 kg m²

The angular momentum of the bullet about the center of rod = mvr

where m is mass , v is perpendicular component of velocity of bullet and r is distance of point of impact of bullet fro center .

5 x 10⁻³ x v sin60 x .11 x .5  where v is velocity of bullet

According to law of conservation of angular momentum

5 x 10⁻³ x v sin60 x .11 x .5 = ( I + mr²)ω , where ω is angular velocity of bullet rod system and  ( I + mr²) is moment of inertia of bullet rod system .

.238 x 10⁻³ v = ( .004638 + 5 x 10⁻³ x .11² x .5² ) x 12

.238 x 10⁻³ v = ( .004638 + .000015125 ) x 12

.238 x 10⁻³ v = 55.8375 x 10⁻³

.238 v = 55.8375

v = 234.6 m /s

4 0
3 years ago
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