The force of the tripped catch exerted on the 2.5 Kg ball moving at 8.5 m/s to the Left is 160 N
<h3>Data obtained from the question </h3>
- Initial velocity (u) = 8.5 m/s
- Final velocity (v) = 7.5 m/s
- Time (t) = 5 ms = 0.25 s
- Mass (m) = 2.5 Kg
- Force (F) = ?
<h3>How to determine the force</h3>
The force exerted on the ball can be obtained as follow:
F = m(v + u) / t
F = [2.5(7.5 + 8.5)]/ 0.25
F = 40 / 0.25
F = 160 N
Thus, the force exerted on the ball is 160 N
Learn more about momentum:
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The remains of Mesosaurus- a crocodile-like reptilian tells United States that South America, Africa and Antarctica were once joined along which implies they were once an enormous continent. However, because of the idea called the geological phenomenon, this one massive continent began to break so making individual continents.
The answer will be 50N.
This is because the spring reads weight and weight is mass times acceleration due to gravity.5kg*10m/s2=50N
Answer:
<h2>6 g/cm³</h2>
Explanation:
The density of a substance can be found by using the formula
From the question
mass = 36 g
volume = 6 cm³
We have
We have the final answer as
<h3>6 g/cm³</h3>
Hope this helps you
