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marissa [1.9K]
3 years ago
12

The activation energy for the isomerization reaction of CH3NC in Problem 14 is 161 kJ mol 1, and the reaction rate constant at 6

00 K is 0.41 s 1. (a) Calculate the Arrhenius factor A for this reaction. (b) Calculate the rate constant for this reaction at 1000 K.

Physics
1 answer:
astraxan [27]3 years ago
5 0

Answer:

Explanation:

Below is an attachment containing the solution to the question.

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At the end of the adiabatic expansion, the gas fills a new volume V₁, where V₁ > V₀. Find W, the work done by the gas on the
tino4ka555 [31]

Answer:

W=\frac{p_0V_0-p_1V_1}{\gamma-1}

Explanation:

An adiabatic process refers to one where there is no exchange of heat.

The equation of state of an adiabatic process is given by,

pV^{\gamma}=k

where,

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k = constant

Therefore, work done by the gas during expansion is,

W=\int\limits^{V_1}_{V_0} {p} \, dV

=k\int\limits^{V_1}_{V_0} {V^{-\gamma}} \, dV

=\frac{k}{\gamma -1} (V_0^{1-\gamma}-V_1^{1-\gamma})\\

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4 0
3 years ago
Please help me with this question
valkas [14]

Answer: m∠P ≈ 46,42°

because using the law of sines in ΔPQR

=> sin 75°/ 4 = sin P/3

so ur friend is wrong due to confusion between edges

+) we have: sin 75°/4 = sin P/3

=> sin P = sin 75°/4 . 3 = (3√6 + 3√2)/16

=> m∠P ≈ 46,42°

Explanation:

4 0
3 years ago
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