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suter [353]
2 years ago
15

My mass is 65 kg and on Earth this equals a weight of 640 N, but on the moon where gravity is 1.7 m/s² my

Physics
1 answer:
Helen [10]2 years ago
4 0

Your weight on the moon given the data from the question is 110.5 N

<h3>Definition of mass and weight </h3>

Mass is simply defined as the quantity of matter present in an object. The mass of an object is constant irrespective of the location of the object.

Weight is simply defined as the gravitational pull on an object. The weight of an object varies from place to place due to gravity.

<h3>Relationship between mass and weight </h3>

Mass and weight are related according to the following equation

Weight (W) = mass (m) × Acceleration due to gravity (g)

<h3>How to determine the weight on the moon</h3>
  • Mass (m) = 65 Kg
  • Acceleration due to gravity on the moon (g) = 1.7 m/s²
  • Weight (W) =?

W = mg

W = 65 × 1.7

W = 110.5 N

Learn more about mass and weight:

brainly.com/question/14684564

#SPJ1

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Two astronauts push on a satellite. One pushes in the positive x direction with a force of 42 N, and the other pushes in the pos
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The vectors adition we can find the magnitude of the force applied by the other astronaut is  11.25 N in the y direction

 

Parameters given

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  • Angle θ = 15º

To find

  • Force another astronaut

The force is a vector magnitude for which the addition of vectors must be used, a very efficient method to perform this sum is to add the components of each vector and devise constructing the resulting vector using trigonometry and the Pythagorean theorem.

Let's use trigonometry to find the other force

            tan θ = \frac{F_y}{F_x}

            F_ y = Fₓ tan θ

let's calculate

            F_y = 42 tan 15

            F_y = 11.25 N

Using the summation of vectors we can find the magnitude of the force applied by the other astronaut is 11.25 N in the y direction

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brainly.com/question/15074838

4 0
3 years ago
The variation in the pressure of helium gas, measured from its equilibrium value, is given by ΔP = 2.9 × 10−5 cos (6.20x − 3 000
nadya68 [22]

Answer:

The wavelength of this wave is 1.01 meters.

Explanation:

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On comparing equation (1) and (2) :

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2. Three blocks, A,B and C of mass 2kg. 3kg. 5kg respectively kept side by side with one another are accelerated at 2m/s2 across
gulaghasi [49]

Answer:

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Acceleration produced = 2m/s^2

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Force between 2 kg and 3 kg block = (20-4) = 16N. ans

Net force on 3 kg block = 3 × 2 =6N.

Applied force on 3 kg block due to 2 kg block = 16N.

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answers:-

(a) 20 N

(b) 16N

(c) 10 N

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