The question isn't clear enough, I think it ask us to calculate the linear speed of a point at the edge of the DVD.
Now let's imagine we're a point at the edge of the DVD, we're undergoing a circular motion. Each minute we will complete a circular track 7200 times, now we need to know the distance we travel each turn. The perimeter of the DVD, a circular object is:
![P=2\pi.R](https://tex.z-dn.net/?f=P%3D2%5Cpi.R)
Know recall that:
![v=\frac{d}{t}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bd%7D%7Bt%7D)
We now need to know how much distance is traveled during a minute or 60 seconds:
![D=7200\times 2\pi\times R](https://tex.z-dn.net/?f=D%3D7200%5Ctimes%202%5Cpi%5Ctimes%20R)
Finally we divide this result with t=60 seconds:
![v=\frac{7200\times2\pi\times R}{60} \\ R=\frac{12}{2}=6 ](https://tex.z-dn.net/?f=v%3D%5Cfrac%7B7200%5Ctimes2%5Cpi%5Ctimes%20R%7D%7B60%7D%0A%5C%5C%0AR%3D%5Cfrac%7B12%7D%7B2%7D%3D6%0A)
![v\approx 4523.89 \frac{units}{second}](https://tex.z-dn.net/?f=v%5Capprox%204523.89%20%5Cfrac%7Bunits%7D%7Bsecond%7D)
Where the distance units were named units as the length unit is not specified in this exercise.<span />
The force involved in the orbiting of the earth is gravity!
Answer:
Explanation:
They are called "fictitious" because the physical forces leading to motion are accounted for in the construction of the non-inertial frame rather than being included as a "real force" term in the equation of motion. Instead, the terms are built into the equation of motion itself in a non-inertial frame.
False.
<span>According
to Archimedes’ principle, if an object’s weight is equal to the
weight of the fluid displaced, the object will float.
</span>
The weight of anything in any place is
(mass of the thing) x (acceleration of gravity in that place).
-- On Earth, the acceleration of gravity is about 9.807 m/s²
Weight of 19 kg of mass is (19 kg) x (9.807 m/s²) = <em>186.3 newtons</em>
-- On the Moon, the acceleration of gravity is about 1.623 m/s²
Weight of the same 19 kg of mass is (19 kg) x (1.623 m/s²) = <em>30.8 newtons</em>