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3 years ago

Please help me with this question

Physics

1 answer:

valkas [14]3 years ago

4 0

Answer: m∠P ≈ 46,42°

because using the law of sines in ΔPQR

=> sin 75°/ 4 = sin P/3

so ur friend is wrong due to confusion between edges

+) we have: sin 75°/4 = sin P/3

=> sin P = sin 75°/4 . 3 = (3√6 + 3√2)/16

=> m∠P ≈ 46,42°

Explanation:

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What are Prevailing Westerlies? a Calm area with rising air b Wind blowing West to East away from horse latitudes c Wind blowing

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2 years ago

Suppose that the terminal speed of a particular sky diver is 165 km/h in the spread-eagle position and 320 km/h in the nosedive

coldgirl [10]

Answer:

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3 years ago

Read 2 more answers

An L-C circuit containing an 82.0-mH inductor and a 1.60-nF capacitor oscillates with a maximum current of 0.800 A . Assuming th

ryzh [129]

Answer:

19.5 mJ

Explanation:

Assuming perfect components without resistance or losses, the circuit should oscillate indefinetly.

The circuit will have a natural pulsation of

$w = \frac{1}{\sqrt{L * C}} = \frac{1}{\sqrt{82e-3 * 1.6e-9}} = 87304 rad/s$

$f = \frac{w}{2\pi} = \frac{87304}{2\pi} = 13895 Hz$

$T = \frac{1}{f} = \frac{1}{13895} = 7.2 \mu s$

So, by the time t = 2.4 ms, 333.33 cycles would have passed

$\frac{2.4 ms}{7.2 \mu s} = \frac{2400 \mu s}{7.2 \mu s} = 333.33$

Therefore it would be at one third after the beginning of the cycle. The circuit would be in an equivalent state as t = (7.2 us)/3 = 2.4us

At t=0 the capacitor is fully charged, so the voltage is maximum and the current is 0. The current will increase towards a maximum of 800 mA at t=T/4, then decreas to 0 at t=T/2, decrease to -800 mA at 3T/4 and go back to 0 at t=T following a sine wave.

The equation of this sine wave would be

$I(t) = I0 * sin(w * t)$