Well, gold is way different form other say for instance what if you get a really good ring not to expensive or cheap, but its in between those characteristics what if u get a gold ring to compare now one might tarnish or fade, but if you really look at it that gold one will not it really all dependents on what metals your talking about cause all metals aren't the same some fade and some don't . Also the oxygen level is weak for other metals, but gold it different it can still keeps its shine .
- That's the best explanation i can give IF ITS NOT ENUH OR NOT RIGHT JUH COMMENT BELOWW↓↓ I WILL THINK OF SOMEThING ELSE THANKS! YOU HAVE A GREAT DAYY .
Answer:
Explanation:
a) for 1.000 g X: 0.1621 g Y
ratio of mass of element Y = 2.100g : 0.1621g
= 1 : 0.07
b) 1.000 g X: 0.7391 g Y
ratio of mass of element Y = 2.100g : 0.7391g
= 1: 0.35 , = 20:7
c) 1.000 g X: 0.2579 g Y
ratio of mass of element Y = 2.100g : 0.2579g
= 1 : 0.12
d) 1.000 g X: 0.2376 g Y
ratio of mass of element Y = 2.100g : 0.2376g
= 1: 0.11
e) 1.000 g X: 0.2733 g Y
ratio of mass of element Y = 2.100g : 0.2733g
= 1 : 0.13
From the values obtained , the closest that is in compliance with the law f multiple proportions is option B
The food darkens because the color is changing in the food.
First,
Moles of HBu = Volume per liter * moles of HBu/ liter
= 25ml/1000 * 0.15 = 0.00375 moles
moles of NaOH = volume per liter * moles of NaOH/liter
= 1 ml/1000 * 0.15 = 0.00015 moles
according to this equation:
HBu + NaOH → H2O + NaBu
when 1 mol of NaOH gives 1mol of HBu
So 0.00015 of NaOH will give 0.00015 mol of HBu
∴moles of HBu which remains = 0.00375- 0.00015 = 0.0036 moles
∴moles of Bu- produced = 0.00015 moles
when the total volume = 0.025 + 0.026 =0.051 L
[HBu] = 0.0036moles / 0.051 L = 0.071 moles
[Bu] = 0.00015 / 0.051L = 0.0029 moles
when Ka = [H+] [Bu] / [HBu]
1.5x10^-5 = [H+] (0.0029) /(0.071)
∴[H+] =1x10^-6 / 0.076 = 1.5 x 10^-5
∴PH = -㏒[H+]
= - ㏒ 1.5x10^-5
= 4.81
