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Verizon [17]
3 years ago
6

Suppose that 5 people sitting in an enclosed room are each generating about 500 BTUs of body heat per hour. If the room is 10ft

x15ft x 10ft how many btus per cubic foot do they produce in 3 hours
Mathematics
2 answers:
grigory [225]3 years ago
8 0

Answer:

1

Step-by-step explanation:

500/hour    1500/3hours

10*15*10=1500

so for every cubic foot is one btu

Mrrafil [7]3 years ago
7 0

Answer:

the answer is 5 BTUs/ft^3

Step-by-step explanation:

first: 10x15x10= 1500 ft ^3

second: 500 BTUs x 5 people= 2500 BTUs by all five people

third: 2500 BTUs x 3 hrs= 7500 BTUs per 3 hrs

lastly: divide 7500 BTUs by 1500 ft ^3 to get 5 BTUs/ ft^3

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Answer: $‭1,135.15‬

Step-by-step explanation:

First calculate his basic pay;

= 40 * 14.60

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= 584 + 273.75 + 131.40 + 146

= $‭1,135.15‬

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This Venn diagram represents the science subjects studied by students. What is the probability that a student, chosen at random,
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A truck loaded with 8000 electronic circuit boards has just pulled into a firm’s receiving dock. The supplier claims that no mor
Juliette [100K]

Answer:

The 95% confidence interval for the proportion of all boards in this shipment that fall outside the specification is (1.8%, 6.2%).

Step-by-step explanation:

Let <em>X</em> = number of boards that fall outside the most rigid level of industry performance specifications.

In a random sample of 300 boards the number of defective boards was 12.

Compute the sample proportion of defective boards as follows:

\hat p =\frac{12}{300}=0.04

The (1 - <em>α</em>)% confidence interval for population proportion <em>p</em> is:

CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

The critical value of <em>z</em> for 95% confidence level is,

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

*Use a <em>z</em>-table.

Compute the 95% confidence interval for the proportion of all boards in this shipment that fall outside the specification as follows:

CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}\\=0.04\pm1.96\sqrt{\frac{0.04(1-0.04)}{300}}\\=0.04\pm0.022\\=(0.018, 0.062)\\\approx(1.8\%, 6.2\%)

Thus, the 95% confidence interval for the proportion of all boards in this shipment that fall outside the specification is (1.8%, 6.2%).

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3 years ago
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