Answer:
A pumpkin or a deer cus it's hunting season
So,
Our conceptual plan is as follows:
g AlCl3 --> mol AlCl3 --> mol H2 --> g H2
![\frac{129g\ AlCl_3}{133.4g/mol}\ *\frac{3mol\ H_2}{2mol\ AlCl_3}\ *2.016g/mol \\ \\=2.92 g\ H_2](https://tex.z-dn.net/?f=%5Cfrac%7B129g%5C%20AlCl_3%7D%7B133.4g%2Fmol%7D%5C%20%2A%5Cfrac%7B3mol%5C%20H_2%7D%7B2mol%5C%20AlCl_3%7D%5C%20%2A2.016g%2Fmol%20%5C%5C%20%5C%5C%3D2.92%20g%5C%20H_2)
Hope this helps!
Answer:
![Tablets=193](https://tex.z-dn.net/?f=Tablets%3D193)
Explanation:
Hello,
In this case, given that a typical aspirin tablet contains 5.00 grains of pure aspirin, the first step here is to compute the mass of those grans per tablet given that 1.00 g = 15.4 grains:
![m=5.00grains*\frac{1.00g}{15.4grains}=0.325g](https://tex.z-dn.net/?f=m%3D5.00grains%2A%5Cfrac%7B1.00g%7D%7B15.4grains%7D%3D0.325g)
In such a way, the number of aspirin tablets are computed considering the total mass of aspirin and the mass per tablet:
![Tablets=\frac{62.7g}{0.325g}\\ \\Tablets=193](https://tex.z-dn.net/?f=Tablets%3D%5Cfrac%7B62.7g%7D%7B0.325g%7D%5C%5C%20%5C%5CTablets%3D193)
Best regards.
Answer:
A)
<u>4, 7, 4, 6</u>
B)
<u>12 moles</u>
Explanation:
![NH_{3}(g) + O_{2}(g) \: → NO_{2} + H_{2}O(g)](https://tex.z-dn.net/?f=%20NH_%7B3%7D%28g%29%20%2B%20O_%7B2%7D%28g%29%20%5C%3A%20%E2%86%92%20NO_%7B2%7D%20%2B%20H_%7B2%7DO%28g%29)
__↑______↑
8.00 mol | 14.00 mol
________________
![NH_{3}(g) + O_{2}(g) \: → NO_{2} + H_{2}O(g)](https://tex.z-dn.net/?f=%20NH_%7B3%7D%28g%29%20%2B%20O_%7B2%7D%28g%29%20%5C%3A%20%E2%86%92%20NO_%7B2%7D%20%2B%20H_%7B2%7DO%28g%29)
You can turn this into a system of variables which are solvable.
To do this, create variables for the coefficients of each compound in the reaction respectively.
![a(NH_{3}(g)) + b(O_{2}(g)) → \\c(NO_{2}) + d(H_{2}O(g))](https://tex.z-dn.net/?f=%20a%28NH_%7B3%7D%28g%29%29%20%2B%20b%28O_%7B2%7D%28g%29%29%20%E2%86%92%20%5C%5Cc%28NO_%7B2%7D%29%20%2B%20d%28H_%7B2%7DO%28g%29%29)
Because to be balanced, the count of atoms in each element of the compound correspond to the coefficient of the variable in that compound so that the count of the left (reactant) side is set equal to the right (product) side.
a corresponds to the coefficient of the first compound, b corresponds to the coefficient of the second compound, c corresponds to the coefficient of the third compound, and d corresponds to the coefficient of the fourth compound.
(Reactant = Product)
Reactant: 1a [N] Product: 1c.
Reactant: 3a [H] Product: 2d.
Reactant: 2b [O] Product: 2c + 1d.
Thus the system is:
1a = 1c
3a = 2d
2b = 2c + 1d.
Then just use the substitution methods to solve.
The chain reaction is easy to stop. Just add a neuron absorbing material. The Control Rods in rectors can do that You just SCRAM (put the rods all the way in) or add something like Boron and the chain reaction stops.
<span>The problem is the radioactive waste. Those isotopes break down and release heat spontaneously, no neutrons required. The only known way to stop or slow radioactive decay down is to slow time down by moving at relativistic speed or near orbit to a black hole.</span>