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3 years ago

Find the 20th term of this sequence. -2,4,-8,16

Mathematics

1 answer:

Ivenika [448]3 years ago

8 0

Answer:

1,048,576

Step-by-step explanation:

You should multiply it with -2 20 times

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X2 + 6x +9<br> x² - 4x - 21

Jlenok [28]

Answer:

=8×+9

=(x+3)×(x-7)

Step-by-step explanation:

i think I'm correct

6 0

2 years ago

A woman bought 210

artcher [175]

Answer:

Profit = 75

Step-by-step explanation:

Selling price of 3 oranges = 2

There are 210÷3 = 70 set of oranges

Selling price of 1 set (3 oranges) of orange = 2

Selling price of 70 set of oranges = 70 * 2 = 140

Cost of 210 oranges = 65

Profit = selling price - cost price

= 140 - 65

= 75

7 0

2 years ago

-b+10a-5 in standard form

ludmilkaskok [199]

Answer:

10a-b-5

Step-by-step explanation:

-b+10a-5 in standard form

10a-b-5

hoped this helped :)

7 0

3 years ago

write an expression that describes the number of points scored on touchdowns t and points after touchdowns p by one team in a ga

Len [333]

A touchdown is scored 6 points for each touchdown and the points made after a touchdown is scored 2 points each. We are given the following variables:

t = number of touchdowns
p = number of points after a touchdown

Total score = 6t + 2p

Where 6 times t is the total score given by the number of touchdowns multiplied by 6 points, the same goes for the expression 2p.

6 0

2 years ago

Newton's law of cooling states that the temperature of an object changes at a rate proportional to the difference between its te

Aleonysh [2.5K]

Answer:

t=5.18 minute

Step-by-step explanation:

Using Newton's law of cooling

$\frac{dT}{dt}=-k(T-T_{s})$

T is temperature of a cup of coffee at any time t $T_{s}$ , is the temperature of the surrounding and k is a constant of proportionality in this negative because temperature is decreasing.

$T(0)=190\\T(1)=170\\T_{s}=66$

$\frac{dT}{dt}=-k(T-T_{s})\\\frac{dT}{(T-T_{s})}=-k*dt\\\int\limits {\frac{1}{T-T_{s} } } \, dT=-\int\limits {k} \, dt\\ln(T-T_{s})=k*t+C\\e*ln(T-T_{s})=e^{k*t+C} \\T-T_{s}=e^{k*t}*e^{C}\\e^{C}=C\\T-T_{s}=e^{k*t}*C\\T=T_{s}+e^{k*t}*C$

To find constant knowing the time and the temperature the first step of the change of energy in cup of coffee

$T=T_{s} +e^{-k*t}*C\\ C=190-66=124\\170=66+124*e^{-k*2}\\ 170-66=124*e^{-k*2}\\ln(\frac{104}{124})=ln*e^{-k*2}\\-0.175=-k*2\\k=0.08794$

Now using the constant of decreasing can find the time to be a 145 temperature the cup of coffee

$145=66+124*e^{-k*t} \\145-66=124*^{-0.087*t}$

$ln(0.637)=ln*e(-0.087*t)\\-0.45=-0.087*t\\t=5.18minutes$

4 0

3 years ago