Answer:
pang anong grade po yan kasi grade 4 palang po
kasi ako
Answer:
- 0.25m/s²
Explanation:
Given parameters:
Initial velocity = 40m/s
Final velocity = 30m/s
Time taken = 40s
Unknown:
Acceleration of the car = ?
Solution:
Acceleration is the rate of change of velocity with time.
So;
Acceleration = 
Acceleration = 
= - 0.25m/s²
This implies that the car will decelerate at a rate of 0.25m/s²
Answer:
correct option is d) 7.0 x 10^-7 N
Explanation:
given data
distance = 175 picometers = 1.75 × 
m
to find out
electrical force
solution
we know atomic no of uranium is 92
and charge on electron is = 1.6 × 
C
and electrical force is express as
electrical force = 
.............1
put here value we get
electrical force = 
electrical force = 6.921 × 
N
so correct option is d) 7.0 x 10^-7 N
Answer:
C) 50 m/s
Explanation:
With the given information we can calculate the acceleration using the force and mass of the box.
Newton's 2nd Law: F = ma
- 5 N = 1 kg * a
- a = 5 m/s²
List out known variables:
- v₀ = 0 m/s
- a = 5 m/s²
- v = ?
- Δx = 250 m
Looking at the constant acceleration kinematic equations, we see that this one contains all four variables:
Substitute known values into the equation and solve for v.
- v² = (0)² + 2(5)(250)
- v² = 2500
- v = 50 m/s
The final velocity of the box is C) 50 m/s.
Answer:
C. At the instant the ball reaches its highest point.
Explanation:
When a body is thrown up, it tends to come down due to the influence of gravitational force acting on the body. The body will be momentarily at rest at its maximum point before falling. At this maximum point, the velocity of the body is zero and since force acting on a body is product of the mass and its acceleration, the force acting on the body at that point will be "zero"
Remember, F = ma = m(v/t)
Since v = 0 at maximum height
F = m(0/t)
F = 0N
This shows that the force acting on the body is zero at the maximum height.
