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DENIUS [597]
3 years ago
11

Does chess make you smarter?

Physics
1 answer:
Yuliya22 [10]3 years ago
5 0
Chess does not necessarily make you smarter it makes you better in terms of being patient, strategic, and better at counter-attacking   
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How do i solve this step by step
NikAS [45]

Answer:

176.4 meters

Explanation:

The first equation is for average velocity.  The other three are the constant acceleration equations you'll need to know.

v = at + v₀

v² = v₀² + 2a(x − x₀)

x = x₀ + v₀ t + ½ at²

x is the final position

x₀ is the initial position

v is the final velocity

v₀ is the initial velocity

t is time

a is acceleration

Notice that the first equation is independent of position.

The second equation is independent of time.

The third equation is independent of final velocity.

So knowing which information you <em>don't</em> have will point you to which equation you should use.

Let's begin:

"Which one would be best to find the distance the object fell from free-fall if it fell for six seconds, assuming if fell in the absence of air resistance and it still hasn't hit the ground?  Solve this problem and show all steps of work."

We want to find the distance (change in position).  We're given the time (t = 6 s) and we're given the acceleration (free fall without air resistance, so a = -9.8 m/s²).

We aren't given the final velocity, so the equation we should use is the third one:

y = y₀ + v₀ t + ½ at²

Unfortunately, we aren't told the initial velocity, but if we assume that the object starts at rest, then v₀ = 0 m/s.  Substituting all values:

y = y₀ + (0 m/s) (6 s) + ½ (-9.8 m/s²) (6 s)²

y − y₀ = -176.4 m

The displacement is -176.4 m.  Distance is the magnitude of displacement, so we can say the object fell 176.4 meters.

3 0
3 years ago
A 3.39-kg block is sliding down a 7.92-kg frictionless incline. Both are initially moving to the right at 10.3 m/s. q7 (a) If th
Agata [3.3K]

Answer:

Final Speed of Incline = 5.549 m/s

Explanation:

To answer this question, we must remember the fact that any momentum gained by the block is equal to the momentum lost by the incline.

So lets start by find the initial and final momentum of the box in the horizontal direction:

Initial Momentum = mass * initial velocity

Initial Momentum = 3.39 * 10.3 = 34.917   kg*m/s

Final Momentum = mass * final velocity

Final Momentum = 3.39 * 21.4 = 72.546 kg*m/s

Change in momentum: 72.546 - 34.917 = 37.629 kg*m/s

This is equal to the momentum lost by the incline.

Initial momentum of incline = 7.92 * 10.3 = 81.576 kg*m/s

Final momentum of incline = 81.576 - 37.629 = 43.947 kg*m/s

Plugging this into the momentum equation to find the speed:

Final Speed * Mass = Final Momentum

Final Speed = 43.947 / 7.92

Final Speed = 5.549 m/s

3 0
3 years ago
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