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DENIUS [597]
4 years ago
11

Does chess make you smarter?

Physics
1 answer:
Yuliya22 [10]4 years ago
5 0
Chess does not necessarily make you smarter it makes you better in terms of being patient, strategic, and better at counter-attacking   
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A horse pulls on a carriage. By Newton's third law, the carriage pulls back on the horse with equal force. Why do the action and
Andrews [41]

Answer:

By Newton's third law the cart must then exert an equal and opposite force on the horse. ... If it doesn't accelerate, and it started it rest, it must remain at rest (by the definition of acceleration), and therefore no matter how hard the horse pulls, it can never move the cart

5 0
3 years ago
If 5kg Stone and 1kg stone throw the from the building which will land more fa ster and why?​
sweet [91]

Answer:

Both stones will land at the same time because both stones will fall with the same acceleration through the same height.

Explanation:

We are given that

Mass of stone ,m1=5 Kg

Mass of stone, m2=1 kg

We have to find which stone more faster will land and why.

h=u+\frac{1}{2}gt^2

Initial velocity of both stones=0

h=\frac{1}{2}gt^2

t^2=\frac{h}{g}

t=\sqrt{\frac{h}{g}}

t_1=t_2=\sqrt{\frac{h}{g}}

Because both stones are thrown from the same height.

Both stones will land at the same time because both stones will fall with the same acceleration through the same height  and the acceleration  does not depend of its mass.

5 0
3 years ago
The magnetic field at the centre of a toroid is 2.2-mT. If the toroid carries a current of 9.6 A and has 6.000 turns, what is th
ziro4ka [17]

Answer:

Radius, r = 0.00523 meters

Explanation:

It is given that,

Magnetic field, B=2\ mT=2.2\times 10^{-3}\ T

Current in the toroid, I = 9.6 A

Number of turns, N = 6

We need to find the radius of the toroid. The magnetic field at the center of the toroid is given by :                  

B=\dfrac{\mu_oNI}{2\pi r}

r=\dfrac{\mu_oNI}{2\pi B}  

r=\dfrac{4\pi \times 10^{-7}\times 6\times 9.6}{2.2\pi \times 2\times 10^{-3}}  

r = 0.00523 m

or

r=5.23\times 10^{-3}\ m

So, the radius of the toroid is 0.00523 meters. Hence, this is the required solution.

7 0
3 years ago
Read 2 more answers
Question 4 A car of mass 820 kg has a maximum power of 30 kW and moves against a constant resistance of motion to 910 N. Calcula
wolverine [178]

Answer:

P = W / t = m g s / t = m g v       where work by auto = m g s

30 kw = 30000 watts = 30000 J / s

Work wasted = F v       as shown above relating work and power

Work done against incline = m g s sin 8.75  and power against incline

= m g v sin 8.75 = 1222 v Joules / sec

power in moving auto = power available - power lost to friction

power in moving auto = 30000 - resistance = 30000 - 910 v

1222 v = 30000 - 910 v

v = 30000 / 2132 = 14 m/s

Note: constant resistance to motion must mean P = W / t = F s / t = F v

7 0
3 years ago
You are camping with two friends, Joe and Karl. Since all three of you like your privacy, you don't pitch your tents close toget
Lemur [1.5K]

Answer:

Distance between Karl and Joe is 38.467 m

Solution:

Let us assume that you are at origin

Now, as per the question:

Joe's tent is 19 m away from yours in the direction 19.0^{\circ} north of east.

Now,

Using vector notation for Joe's location, we get:

\vec{r_{J}} = 19cos(19.0^{\circ})\hat{i} + 19sin(19.0^{\circ})\hat{j}

\vec{r_{J}} = 17.96\hat{i} + 6.185\hat{j} m

Now,

Karl's tent is 45 m away from yours and is in the direction 39.0^{\circ}south of east, i.e.,  - 39.0^{\circ} from the positive x-axis:

Again,  using vector notation for Karl's location, we get:

\vec{r_{K}} = 45cos(-319.0^{\circ})\hat{i} + 45sin(- 39.0^{\circ})\hat{j}

\vec{r_{K}} = 34.97\hat{i} - 28.32\hat{j} m

Now,  obtain the vector difference between \vec{r_{J}} and \vec{r_{K}}:

\vec{r_{K}} - \vec{r_{J}} = 34.97\hat{i} - 28.32\hat{j} - (17.96\hat{i} + 6.185\hat{j}) m

\vec{d} = \vec{r_{K}} - \vec{r_{J}} = 17.01\hat{i} - 34.51\hat{j} m

Now, the distance between Karl and Joe, d:

|\vec{d}| = |17.01\hat{i} - 34.51\hat{j}|

d = \sqrt{(17.01)^{2} + (34.51)^{2}} m

d = 38.469 m

The distance between Karl's and Joe's tent is:

7 0
4 years ago
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