Answer:
a) wavelength = 656.3 nm
b) the value of Rydberg's constant for this measurement is 1.097 × 10⁷ m⁻¹
Explanation:
Given that;
angle of diffraction Θₓ = 22.78°
incident angle Θ₁ = 0
slit separation d = 5900 lines per cm = 1/5900 cm = 10⁻²/5900 m = 0.01/5900 m
order of diffraction n = 1
wavelength λ = ?
to find the wavelength, we use the expression
λ = d (sinΘ₁ + sinΘₓ) / n
To find the wavelength λ;
λ = 0.01/5900 × (sin0 + sin22.78° )
λ = 6.5626 × 10⁻⁷ m
λ = 656.3 x 10⁻⁹ m
∴ λ = 656.3 nm
b)
According Balnur's series spectral lines; n₁ = 3, n₂ = 2 and
λ = R [ 1/n₂² - 1/n₁²]
where R is Rydberg's constant
from λ = R [ 1/n₂² - 1/n₁²]
R = 1/λ [n₂²n₁² / n₁² - n₂²]
R = 10⁹/ 656.3 [ 9 × 4 / 9 - 4 ]
R = 1.097 × 10⁷ m⁻¹
Therefore the value of Rydberg's constant for this measurement is 1.097 × 10⁷ m⁻¹
Explanation:
Given that,
Initial speed of the billiard ball 1, u = 30i cm/s
Initial speed of another billiard ball 2, u' = 40j cm/s
After the collision,
Final speed of first ball, v = 50 cm/s
Final speed of second ball, v' = 0 (as it stops)
Let us consider that both balls have same mass i.e. m
Initial kinetic energy of the system is :
Final kinetic energy of the system is :
The change in kinetic energy of the system is equal to the difference of final and initial kinetic energy as :
So, the change in kinetic energy of the system as a result of the collision is equal to 0.
Answer:
Concave Lens Uses. Telescope and Binoculars Spectacles Lasers Cameras FlashlightsPeepholes. ...
Used in telescope and binoculars. ...
Concave lens used in glasses. ...
Uses of concave lens in lasers. ...
Use of concave lens in cameras. ...
Used in flashlights. ...
Concave lens used in peepholes.
Answer:
a) 0.81 A
b) 0.33 A , 0.48 A
c) 10 Volts , 10 volts
Explanation:
= 30 Ω
= 21 Ω
= Voltage of the battery = 10 Volts
a)
Parallel combination of resistance is given as
Ω
= Total current flowing through the circuit
Total current flowing through the circuit is given as
A
b)
In parallel, Voltage remain same.
= Potential difference across R₁ = 10 Volts
= Potential difference across R₂ = 10 Volts
Current flowing through individual resistors is given as
A
A
c)
In parallel, Voltage remain same, hence
= = 10 Volts