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Butoxors [25]
3 years ago
7

−15(2−3b)−11(4b−3), if b=−2

Mathematics
2 answers:
RoseWind [281]3 years ago
6 0

-15(2+6)-11(-8-3)

= 120+121

= 242

adell [148]3 years ago
6 0

Answer:

1

Step-by-step explanation:

to solve -15(2 - 3b) - 11(4b - 3), plug in -2 for b

-15(2 - 3(-2) - 11(4(-2) - 3) < subsitute -2 for b

-15(2 + 6) - 11 (-8 - 3) < add/ subtract terms in parentheses

-15(8) - 11(-11)  < multiply numbers

-120 + 121 = 1 < add

the solution to the equation is 1

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Estimate the sum of 672 and 830 by rounding to the nearest hundred before adding.
Nitella [24]

Answer:

you round off to the nearest hundred which is 672 and 830 which I find to to 672 and 830 becomes 1000

4 0
3 years ago
Read 2 more answers
(1 point) Suppose we want a 95% confidence interval for the average amount spent on books by freshmen in their first year at col
Ne4ueva [31]

Answer:

a) n=(\frac{1.960(16)}{5})^2 =39.33 \approx 40

So the answer for this case would be n=40 rounded up to the nearest integer

b) For this case if we see the formula for the margin of error

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    (a)

We can see that the margin of error is inversely proportional to the sample size so if we want a samller margin of error we need a LARGER sample

Answer: LARGER

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean

\sigma=16 represent the population standard deviation

n represent the sample size  

Solution to the problem

Part a

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    (a)

And on this case we have that ME =5 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got z_{\alpha/2}=1.960, replacing into formula (b) we got:

n=(\frac{1.960(16)}{5})^2 =39.33 \approx 40

So the answer for this case would be n=40 rounded up to the nearest integer

Part b

For this case if we see the formula for the margin of error

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    (a)

We can see that the margin of error is inversely proportional to the sample size so if we want a samller margin of error we need a LARGER sample

Answer: LARGER

5 0
3 years ago
The number of books checked out from the library varies directly with the number of book reports assigned. there were 3375 books
yan [13]
3375/225=15
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5 0
3 years ago
What is the area of the trapezoid?
EastWind [94]

Answer:

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Step-by-step explanation:

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7 0
2 years ago
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What are the solutions to the quadratic equation 2x^2-8x-24=0
Vinvika [58]

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First, we can factor a 2 out of this expression to simplify it.

2(x^2 - 4x - 12)

Now, we can try factoring this two ways: by using the quadratic formula, or by using the AC method.

We're gonna try using the AC method first.

List factors of -12.

1 * -12

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2 * -6

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Split the middle term.

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Factor by grouping.

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Rearrange terms.

<h3><u>(2)(x + 6)(x - 2) is the fully factored form of the given polynomial.</u></h3>
7 0
3 years ago
Read 2 more answers
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