The empirical formula for the unknown compound would be: C2H4O (2 molecules of Carbon, 4 molecules of Hydrogen, and 1 molecule of Oxygen)
I think the correct answer is b. Temperature is proportional to the average kinetic energy so when temperarure rises so will the average kinetic energy. I hope this helps. Let me know if anything is unclear.
Colloid
Explanation:
A lotion of this type is a typical colloid mixture.
- A colloid is a homogeneous mixtures of two phases.
- The dispersed phase and the dispersion medium.
- Water is the dispersion medium and oil is the dispersed phase.
They have the following properties:
- Liquid dispersed phase and liquid dispersion medium forms an emulsion and a lotion of this type is an example.
- The particles are larger than those found in solutions.
- The particles pass through ordinary filter paper.
- They may be cloudy or clear .
learn more:
Heterogeneous mixtures brainly.com/question/1446244
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6CO2 + 6H20 + (energy) → C6H12O6 + 6O2
aka
Carbon dioxide+water+energy(from light)=glucose and oxygen
Answer:
A. Theoretical yield = 3.51g
B. %yield = 75%
Explanation:
The balanced equation for the reaction is given below:
C2H4 + 3O2 —> 2CO2 + 2H2O
Molar Mass of O2 = 16 x 2 = 32g/mol
Mass of O2 from the balanced equation = 3 x 32 = 96
Molar Mass of H20 = (2x1) + 16 = 18g/mol
Mass of H2O from the balanced equation = 2 x 18 = 36g
A. From the equation,
96g of O2 produced 36g of H2O
Therefore, 9.35g of O2 will produce = (9.35 x 36)/96 = 3.51g of H2O
Therefore,theoretical yield of water (H2O) = 3.51g
B. Theoretical yield = 3.51
Actual yield = 2.63g
%yield =?
%yield = Actual yield/Theoretical yield x 100
%yield = 2.63/3.51
%yield = 75%
