Ask question

Ask question

All categories

marshall27 [118]

3 years ago

5

At what temperature will water change from a solid to a liquid (melt)?

2 answers:

lord [1]3 years ago

8 0

Answer:

When a solid reaches the temperature of its melting point, it can become a liquid. For water, the temperature needs to be a little over zero degrees Celsius (0oC) for you to melt.

enyata [817]3 years ago

3 0

Answer: 0 degrees celsius

Explanation:

There is a special temperature for every substance called the melting point. When a solid reaches the temperature of its melting point, it can become a liquid. For water, the temperature needs to be a little over zero degrees Celsius (0oC) for you to melt.

You might be interested in

The electron configuration for aluminum (Al) is shown below:

Serjik [45]

Answer:

It is the third choice

Explanation:

Just did assignment

3 0

3 years ago

Which of the following pairs of elements is most likely to form an ionic bond?

balu736 [363]

A pair of elements will most likely form an ionic bond if one is a metal and one is a nonmetal. These types of ionic compounds are composed of monatomic cations and anions. ( K, Cl)...

4 0

2 years ago

Read 2 more answers

A ball has a mass of 0.5g and a volume of 10mL. Calculate the density

icang [17]

Answer:

0.05g/ml

Explanation:

density is equal to mass over volume check pic for more info

6 0

2 years ago

A sample of oxalic acid (a diprotic acid of the formula H2C2O4) is dissolved in enough water to make 1.00 L of solution. A 100.0

OleMash [197]

<u>Answer:</u> The mass of original oxalic acid sample is 6.75 grams

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $H_2C_2O_4$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=2\\M_1=?M\\V_1=100.0mL\\n_2=1\\M_2=0.750M\\V_2=20.0mL$

Putting values in above equation, we get:

$2\times M_1\times 100.0=1\times 0.750\times 20.0\\\\M_1=\frac{1\times 0.750\times 20.0}{2\times 100.0}=0.075M$

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}$

Given mass of oxalic acid = ? g

Molar mass of oxalic acid = 90 g/mol

Molarity of solution = 0.075 M

Volume of solution = 1.00 L

Putting values in above equation, we get:

$0.075M=\frac{\text{Mass of oxalic acid}}{90g/mol\times 1L}\\\\\text{Mass of oxalic acid}=(0.075\times 90\times 1)=6.75g$

Hence, the mass of original oxalic acid sample is 6.75 grams

7 0

2 years ago

What is the Arrhenius definition of an acid

matrenka [14]

The answer to your question is,

An Arrhenius acid is a type of substance that separates in water to form Hydrogen ions.

-Mabel <3

8 0

3 years ago

Read 2 more answers