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Nutka1998 [239]
3 years ago
15

A deck of cards has a 5 pink, 2 gray, And 6 black cards. You pick two cards from the deck without replacement. What is the proba

bility that the first card is gray and the second card is pink?
Mathematics
2 answers:
Dahasolnce [82]3 years ago
8 0

Answer:

<u>The probability that the first card is gray and the second card is pink= 5/78</u>

Step-by-step explanation:

A deck of cards has a 5 pink, 2 gray, And 6 black cards.

The total cards = 5 + 2 + 6 = 13

You pick two cards from the deck without replacement.

The probability that the first card is gray = 2/13

The remaining cards = 13 - 1 = 12

The probability that the second card is pink = 5/12

So,

The probability that the first card is gray and the second card is pink =

  = 2/13 * 5/12 = 10/156 = 5/78

Alborosie3 years ago
5 0

5/78 = 6.4%

Answer:

5/78 = 6.4%

Step-by-step explanation:

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Step-by-step explanation:

5 0
3 years ago
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In an ore, 9.8% of its total weight is metal. How many pounds of metal are in 1,950 lb of ore?
Fudgin [204]

Answer

Find out the  how many pounds of metal are in 1,950 lb of ore .

To proof

let us assume that the pounds of metal are in 1,950 lb of ore be x .

As given

In an ore, 9.8% of its total weight is metal.

ore weight = 1,950 lb

9.8% is written in the decimal form

= \frac{9.8}{100}

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5 0
3 years ago
4.20. According to a report released by the National Center for Health Statistics, 51% of U.S. households has only cell phones (
Sergeu [11.5K]

Answer:

The probability that the household has only cell phones and has high-speed Internet is 0.408

Step-by-step explanation:

Let A be the event that represents U.S. households has only cell phones

Let B be the event that represents U.S. households have high-speed Internet.

We are given that 51% of U.S. households has only cell phones

P(A)=0.51

We are given that 70% of the U.S. households have high-speed Internet.

P(B)=0.7

We are given that U.S. households having only cell phones, 80% have high-speed Internet. A U.S household is randomly selected.

P(B|A)=0.8

\frac{P(A\capB)}{P(A)}=0.8\\P(A\capB)=0.8 \times P(A)\\P(A\capB)=0.8 \times 0.51\\P(A\capB)=0.408

Hence the probability that the household has only cell phones and has high-speed Internet is 0.408

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3 years ago
Guys plz i need help badly I don't understand. I need all answers plz. 20 points
Rina8888 [55]

Answer:

ok

Step-by-step explanation:

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