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3 years ago

Is it possible to square root a negative number?

2 answers:

3 0

<span>No because a negative times a negative will be positive and it will not equal a negative number. the square root cannot be one negative and one positive because that is against the definition of a square root.
</span>

Taya2010 [7]3 years ago

3 0

No because you had no number which were negative after you squared. if you do every number goes back positive after you squared it i think.

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The diagram shows a semi circle inside a rectangle of length 140m. the semi circle touches the rectangle at P, Q and R. Calculat

exis [7]

Answer: 250m

Step-by-step explanation:

Length of rectangle = 140m

Length of rectangle = diameter of semicircle = 140m

Therefore, Radius(r) = 140m / 2 = 70m

Perimeter of the shaded region:

Length of tangent at P + length of tangent at Q + shaded portion of arc(AB)

Length of tangent = diameter / 2

Length of tangent = 70m

Perimeter of a circle = 2πr = 2 × 22/7 × 70 = 440m

shaded portion = 440 / 4 = 110m

Therefore, perimeter of shaded portion equals

70m + 70m + 110m = 250m

4 0

3 years ago

A state park charges $5 per car plus $1 per person as an admission fee. The total charged for a car with x people is f(x) = x +

Studentka2010 [4]

Answer:

Given: f(x) = x + 5

If this function changes to $8 per car then

The function: f(x) = x + 8

The concept of equation of straight line: y= mx + b

where b represents the y-intercept

In the equation above, the y-intercept changed from 5 to 8.

The graph will shift 3 units up

7 0

2 years ago

Given points A (1, 2/3), B (x, -4/5), and C (-1/2, 4) determine the value of x such that all three points are collinear

AlladinOne [14]

Answer:

$x=\frac{83}{50}$

Step-by-step explanation:

we know that

If the three points are collinear

then

$m_A_B=m_A_C$

we have

A (1, 2/3), B (x, -4/5), and C (-1/2, 4)

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

step 1

Find the slope AB

we have

$A(1,\frac{2}{3}),B(x,-\frac{4}{5})$

substitute in the formula

$m_A_B=\frac{-\frac{4}{5}-\frac{2}{3}}{x-1}$

$m_A_B=\frac{\frac{-12-10}{15}}{x-1}$

$m_A_B=-\frac{22}{15(x-1)}$

step 2

Find the slope AC

we have

$A(1,\frac{2}{3}),C(-\frac{1}{2},4)$

substitute in the formula

$m_A_C=\frac{4-\frac{2}{3}}{-\frac{1}{2}-1}$

$m_A_C=\frac{\frac{10}{3}}{-\frac{3}{2}}$

$m_A_C=-\frac{20}{9}$

step 3

Equate the slopes

$m_A_B=m_A_C$

$-\frac{22}{15(x-1)}=-\frac{20}{9}$

solve for x

$15(x-1)20=22(9)$

$300x-300=198$

$300x=198+300$

$300x=498$

$x=\frac{498}{300}$

simplify

$x=\frac{83}{50}$

8 0

3 years ago

What is the square root of 74

laiz [17]

Answer:

8.602325

Simplified: 8.6

4 0

3 years ago

Which statement best describes a physical change?

SOVA2 [1]

I think either c or d

3 0

3 years ago

Read 2 more answers