1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Pani-rosa [81]
3 years ago
11

A crate is placed on an adjustable, incline board. the coefficient of static friction between the crate and the board is 0.29.

Physics
1 answer:
sasho [114]3 years ago
7 0

Let the angle be Θ (theta)

Let the mass of the crate be m.

a) When the crate just begins to slip. At that moment the net force will be equal to zero and the static friction will be at the maximum vale.

Normal force (N) = mg CosΘ

μ (coefficient of static friction) = 0.29

Static friction = μN = μmg CosΘ

Now, along the ramp, the equation of net force will be:

mg SinΘ - μmg CosΘ = 0

mg SinΘ = μmg CosΘ

tan Θ = μ

tan Θ = 0.29

Θ = 16.17°

b) Let the acceleration be a.

Coefficient of kinetic friction = μ = 0.26

Now, the equation of net force will be:

mg sinΘ - μ mg CosΘ = ma

a = g SinΘ - μg CosΘ

Plugging the values

a = 9.8 × 0.278 - 0.26 × 9.8 × 0.96

a = 2.7244 - 2.44608

a = 0.278 m/s^2

Hence, the acceleration is 0.278 m/s^2

You might be interested in
Water flows through a 2.5cm diameter pipe at a rate of
My name is Ann [436]

Answer:

From the Bernoulli energy principle,

ΔP + 1/2ρΔv² = 0 -------------------------- eqn 1

where

ΔP = pressure drop = P2 - P1 = (1 - 0.25)x10⁵ N/m =7.5 x 10⁴N/m

Δv²= velocity change = v₂² - v₁²

ρ = water density = 1kg/m3

Recall volumetric flow rate, Q=A v = constant

A = cross sectional area = πr²=πd²/4

d=pipe diameter at point 2 = 2.5cm = 0.025m and Q =0.20m³/min = 0.00333m³/s

So A= 0.000491m²

we can get v2 = Q/A = 6.79m/s

From eqn 1, v₁² = 2(P2 - P1)/ρ + v₂²

v₁² =  (2 x 7.5 x 10⁴)/1000 + 6.79²

v₁² = 196

v₁ = 14m/s

we can now get the area of the constriction point 2, A₁ = Q/v₁

A₁ = 0.000238m² and the diameter now will be d₁

d₁² = 4 x A₁ / π

     = 4 x 0.000238/3.14 = 0.000303m²

d₁ = √0.000303 = 0.0174m

Therefore, the diameter of  a constriction in the pipe  at the new pressure = 0.0174m = 1.74cm

6 0
2 years ago
Gaussian surfaces A and B enclose the same positive point charge. The area of surface A is two times larger than that of surface
svlad2 [7]

Answer:

The total electric flux through the two surfaces is equal.

Explanation:

6 0
3 years ago
When the effect of aerodynamic drag is included, the y‐acceleration of a baseball moving vertically upward is au = −g − kv2, whi
alexira [117]

Answer:

Explanation:

The detailed steps and appropriate integration and differentiation is as shown in the attached files.

au = −g − kv2

ad = −g + kv2

3 0
3 years ago
Three people pull simultaneously on a stubborn donkey. Jack pulls eastward with a force of 64.7 N, Jill pulls with 61.5 N in the
USPshnik [31]

Answer:

 F = 241.8 N    θ = -18.7

Explanation:

To find the net force, we use Newton's second law, for this we decompose the force using trigonomer

Force 2

    F2 = 61.5 N

   cos 45 = F₂ₓ / F2         F₂ₓ = F2 cos 45

   sin 45 = F₂_y / F2          F₂_y = F2 sin 45

     

force 3

     F3 = 171 N

     cos 45 = F₃ₓ / F3

     sin 45 = F₃_y / F3

the total force can be found with its components

axis x direction (East-West)

      Fₓ = 64.7 +61.5 cos 45 + 171 cos 45

      Fₓ = 229.1 N

Y axis (direction North -Sur)

     F_y = 61.5 sin 45 - 171 sin 45

     F_y = - 77,428 N

the resulting force is

      F = Fx i ^ + Fy j ^

      F = (229.1 i⁻ 77,428 j⁾ N

we can use the Pythagorean theorem to find the module

       F = √ (229.1 2 + 77,428 2)

       F = 241.8 N

let's use trigonometry to find the direction

     tan θ = F_y / Fₓ

     θ = tan⁻¹ (F_y / Fₓ)

     θ = tan⁻¹ (-77,428 / 229.1)

     θ = -18.7

4 0
3 years ago
A position-time graph is shown below:
ikadub [295]

Answer: The object moves forward at 5 m/s, stops, and then changes velocity.

Explanation:

With the information given in the question we can graph the points (image attached).

As we can observe, in the first segment of the graph the velocity is increasing linearly (at a constant rate) and is 5 m/s, then in the second segment we can see the position of the object remains the same from second 2 to second 4, which means the object is stopped.

Finally, in the third and last segment, we can observe a change in velocity (at a negative constant rate, because is decreasing), which is decreasing until the object stops.

7 0
2 years ago
Other questions:
  • It takes you 5 min to walk with an average velocity of .75 m/s to the north from the parking lot to the entrance of the amusemen
    13·1 answer
  • Which of the following statements can be inferred given the food web shown above? A. Energy flows from consumers to producers wi
    12·2 answers
  • An electroscope is a fork-shaped device commonly used to detect the presence of charge. The tin leaves of an electroscope will s
    6·1 answer
  • 8. Chemical weathering occurs more rapidly in what kind of climates?
    11·2 answers
  • A police officer uses a radar gun to determine the speed of a car. A specialized radar gun uses ultraviolet light to determine s
    15·1 answer
  • ____________ is an individual sport that helps develop your hand-eye coordination.
    9·1 answer
  • A 0.100-kg ball is thrown with a speed of 20.0 m/s at an angle of 30.0° with the horizontal. Find
    6·1 answer
  • What is TRUE of carbon monoxide?
    5·1 answer
  • When light reflects from a surface, there is a change in its
    6·1 answer
  • When are Waves produced​
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!