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3 years ago

If opposing forces acting on an object are equal, the net force is

Physics

1 answer:

makkiz [27]3 years ago

8 0

Answer:

0 N

Explanation:

suppose, you push a box with 5 N, and another person pushes the box on the opposite side of the box with 5 N, the net force (resultant ) is 0 N, the box will not move if it wasn't moving

hope this helps

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A disk with a uniform positive surface charge density lies in the x-y plane, centered on the origin. The disk contains 2.5 x 10-

allochka39001 [22]

Answer:

E=3 x 10^4 N/c

Explanation:

The electric field strength can be found out disk with a uniform positive surface charge density by

$E= (\sigma/\2epsilon_o)(1-z/ \sqrt(z^2+r^2))$

σ= charge density

r= radius of the disk

z= position in which we have to find electric field = 15 cm

ε_0= constant ( vacuum permitivity)

putting values we get

$E= \frac{2.5\times10^{-6}}{2\times2.5\times10^{-6}}(1-\frac{0.15}{\sqrt{0.15^2+0.075^2} })$

solving we get

E=30000 N/c

E=3 x 10^4 N/c

6 0

3 years ago

Airplane tickets are extremely cheap right now. You decide to take a trip to Paris for a quick weekend vacation. You hop on the

andreyandreev [35.5K]

Answer:

i don't exactly know but im srry for not giving the right answer

Explanation:

6 0

3 years ago

On a cold day, the speed of sound in air is 330 m/s. A note with a frequency of 1,320 Hz is played on an instrument. What is the

Margaret [11]

Wavelength = (speed) / (frequency)

Wavelength = (330 m/s) / (1320/s)

Wavelength = (330/1320) m

Wavelength = 0.25 m

<em>Wavelength = 25 cm</em>

5 0

3 years ago

How much force is exerted if a 250 kg object has an acceleration of 750 m/s2 ?

Andrew [12]

Use Newton’s second law: F=ma
m= 250kg. a= 750ms-2
F= 250 x 750 = 187 500N

6 0

3 years ago

Read 2 more answers

Hello!

Mnenie [13.5K]

Answer:

$T_0=80695.17162...$

Explanation:

Given equation:

$\ln \left(\dfrac{T_0-100}{T_0}\right)=-0.00124$

To solve the given equation:

$\textsf{Apply log rules}: \quad e^{\ln (x)}=x$

$\implies \dfrac{T_0-100}{T_0}=e^{-0.00124}$

Multiply both sides by T₀:

$\implies T_0-100=T_0e^{-0.00124}$

Add 100 to both sides:

$\implies T_0=T_0e^{-0.00124}+100$

Subtract $T_0e^{-0.00124}$ from both sides:

$\implies T_0-T_0e^{-0.00124}=100$

Factor out the common term T₀:

$\implies T_0(1-e^{-0.00124})=100$

Divide both sides by $(1-e^{-0.00124})$

$\implies T_0=\dfrac{100}{1-e^{-0.00124}}$

Carry out the calculation:

$\implies T_0=\dfrac{100}{1-0.99876...}$

$\implies T_0=\dfrac{100}{0.001239231...}$

$\implies T_0=80695.17162...$

6 0

2 years ago