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Mariulka [41]
3 years ago
15

If opposing forces acting on an object are equal, the net force is

Physics
1 answer:
makkiz [27]3 years ago
8 0

Answer:

0 N

Explanation:

suppose, you push a box with 5 N, and another person pushes the box on the opposite side of the box with 5 N, the net force (resultant ) is 0 N, the box will not move if it wasn't moving

hope this helps

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5.25 calories are absorbed by an iron nail. How many joules is this?
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1 kilo-calorie= 4184 joules
0.001 kilo-calorie= 1 calorie

therefore 5.25 calorie=21.966 joules
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3 years ago
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Which statement best describes the positions of the two elements in the periodic table?
vagabundo [1.1K]
The two elements are in the same period, with Element R the first element in the period and Element Q the last element.
4 0
3 years ago
A power plant has two types of transformers. The first type of transformer triples voltage and the second type of transformer re
Stella [2.4K]

Answer:

d . 6 times the secondary turns in the second type of transformer

Explanation:

In transformer , voltage is increased or decreased according to ratio of no of turns in secondary to no of turns in primary coil . The relation is as follows

V₂ / V₁ = n₂/n₁

n₁ and n₂ are no of turns in primary and secondary coil and V₁ and V₂ are voltage in primary and secondary coil.

for first type , Let no of turn in primary = n and no of turn in secondary = n₁

V₂ / V₁ = 3

so

n₁/n  = 3

n = n₁ /3

n₁ = 3n

For second type , let no of turn in secondary = n₂

V₂ / V₁ = .5

n₂/n = .5

n₂ = .5n

n₂ / n₁ = .5n / 3n

n₂ / n₁ = 1 / 6

n₁ = 6n₂

option d is correct .

7 0
3 years ago
would the phases of the moon be affected if the moon didn't make one rotation for each revolution of earth?
Aleks [24]

As long as the moon orbits the Earth in the same way, the phases will be the same.

4 0
3 years ago
2. A small piece of dust is located in between two oppositely charged parallel plates where there exists a uniform electric fiel
Alla [95]

Answer:

a

The total charge is q = 1.6*10^{-4}C

b

The change in potential energy is \Delta U = -4*10^{-2}J

c

The height is  h= 8.2cm

Explanation:

From the question we are told that the

       The magnitude of electric field is E = 5000N/C

        The number of proton is  N_p = 1*10^{15}

        The distance between the plates is  d = 5cm = \frac{5}{100} = 0.05m

The total charge can be mathematically represented as

            q = N_p * e

Where e is the charge on one proton which has a value of =1.6*10^{-19}C

      Substituting values

           q = 1 *10^{15} * 1.6*10^{-19} = 1.6 *10^{-4}C

The change in potential energy is mathematically represented ads

         \Delta U = -(qE)d

where the negative sign shows that the work done by the electric force is against the electric field

                Substituting values

         \Delta U = - 1.6*10^{-4} * 5000 * 0.05

                = -4*10^{-2}J

 

   The mass of the bead is given as 0.05kg

  The change in potential due to gravity is mathematically given as

                    \Delta U = -mgh

the negative sign is  due to the fact that the height is decreasing

And g =9.8m/s^2

                  Making h the subject

        h = \frac{\Delta U}{mg}

Substituting values

                 h = \frac{4*10^{-2}}{0.05 * 9.8}

                   =0.081m = 0.082 *100 = 8.2cm

4 0
4 years ago
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